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Ulleksa [173]
3 years ago
15

The denominator of a rational number is greater than its numerator by 3. If 3 is subtracted from the numerator and 2 is added to

its denominator, the new number becomes 1/5 . find the original number
Mathematics
1 answer:
inn [45]3 years ago
6 0

Answer:

5/8

Step-by-step explanation:

Let the numerator = n.

Let the denominator = d.

The fraction is

n/d

"The denominator of a rational number is greater than its numerator by 3."

d = n + 3

The fraction is

n/(n + 3)

"If 3 is subtracted from the numerator and 2 is added to its denominator, the new number becomes 1/5."

(n - 3)/(n + 3 + 2) = 1/5

(n - 3)/(n + 5) = 1/5

Cross multiply.

5(n - 3) = 1(n + 5)

5n - 15 = n + 5

4n = 20

n = 5

d = n + 3 = 5 + 3 = 8

n/d = 5/8

The original number is 5/8.

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Please answer! Thanks
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3 years ago
An elevator has a placard stating that the maximum capacity is 1600 lb�10 passengers.​ So, 10 adult male passengers can have a m
Bezzdna [24]

Answer:

1. 0.7421 = 74.21% probability the elevator is overloaded.

2. D.​No, there is a good chance that 10 randomly selected people will exceed the elevator capacity.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Assume that weights of males are normally distributed with a mean of 166 lb and a standard deviation of 29 lb​.

This means that \mu = 166, \sigma = 29

Sample of 10.

This means that n = 10, s = \frac{29}{\sqrt{10}}

1.The probability the elevator is overloaded is?

Probability that the sample mean is above 160 pounds, which is 1 subtracted by the p-value of Z when X = 160. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{160 - 166}{\frac{29}{\sqrt{10}}}

Z = -0.65

Z = -0.65 has a p-value of 0.2579.

1 - 0.2579 = 0.7421

0.7421 = 74.21% probability the elevator is overloaded.

2. Does this elevator appear to be​ safe?

High probability of the elevator being overloaded, so not safe. Correct answer is given by option D.

7 0
3 years ago
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