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myrzilka [38]
3 years ago
15

Every day Mr. Jones and Mr. Smith meet for breakfast before work. Every day Mr. Jones spends $1.50 less than Mr. Smith on breakf

ast.
Create a table to show how much money Mr. Jones spends if Mr. Smith spends $4.75, $5.25 and $6.50
Please HELP!
Mathematics
1 answer:
KatRina [158]3 years ago
8 0

Answer:  Mr. Jones spent $15

Step-by-step explanation:

1. You add $4.75, $5.25 and $6.50 all together

2. You subtract that sum by $1.50

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NEED HELP RIGHT AWAY DONT HAVE ANY TIME TO WAIT!!
Fiesta28 [93]
Question 1:
------------------------

Total points = 100
Total question = 40
Type of questions : 2-points question and 4-points questions

Assumed all 40 questions are 2-points questions.
Total points = 40 x 2 = 80

Difference in points = 100 - 80 = 20 points
Difference in the 2 type of questions = 4 - 2 = 2

Number of 4 marks questions = 20 ÷ 2 = 10 

Number of 2 marks questions = 40 - 10 = 30

Answer: There are 10 4-marks questions and 30 2-marks questions.

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Question 2:
------------------------

Let x be the number of offices you need to clean.

Total cost = 315 + 4x
Total revenue = 25x

To break even,
315 + 4x = 25x
21x = 315
x = 15

Answer: You need to clean 15 offices to break even.

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Question 3:
------------------------

Total distance (including return trip) = 255 + 255 = 510 miles

Total time taken = 1.7 + 1.5 = 3.2 hours

Speed = Distance ÷ time

Speed = 510 ÷ 3.2 = 159.38 miles/hour

Answer: The average speed is 159.38 miles/hour

5 0
3 years ago
Read 2 more answers
Sara measures and finds that she can do a vertical jump that is 27% of her height. If she is 63 inches tall, how high (in inches
Tresset [83]

Answer:

sara can jump 17.01 inches high

Step-by-step explanation:

0.27×63=17.01

8 0
3 years ago
Suppose there is a pile of​ quarters, dimes, and pennies with a total value of ​$1.06. ​How much of each coin can be present wit
SpyIntel [72]
Hello,

I note (a,b,c) the result of a quarters, b dimes and c pennies:


2 solutions:
106=( 3, 3, 1)=( 1, 8, 1)



106=( 0, 0, 106) but : 100= 0*25+ 0*10+ 100
106=( 0, 1, 96) but : 100= 0*25+ 1*10+ 90
106=( 0, 2, 86) but : 100= 0*25+ 2*10+ 80
106=( 0, 3, 76) but : 100= 0*25+ 3*10+ 70
106=( 0, 4, 66) but : 100= 0*25+ 4*10+ 60
106=( 0, 5, 56) but : 100= 0*25+ 5*10+ 50
106=( 0, 6, 46) but : 100= 0*25+ 6*10+ 40
106=( 0, 7, 36) but : 100= 0*25+ 7*10+ 30
106=( 0, 8, 26) but : 100= 0*25+ 8*10+ 20
106=( 0, 9, 16) but : 100= 0*25+ 9*10+ 10
106=( 0, 10, 6) but : 100= 0*25+ 10*10+ 0
106=( 1, 0, 81) but : 100= 1*25+ 0*10+ 75
106=( 1, 1, 71) but : 100= 1*25+ 1*10+ 65
106=( 1, 2, 61) but : 100= 1*25+ 2*10+ 55
106=( 1, 3, 51) but : 100= 1*25+ 3*10+ 45
106=( 1, 4, 41) but : 100= 1*25+ 4*10+ 35
106=( 1, 5, 31) but : 100= 1*25+ 5*10+ 25
106=( 1, 6, 21) but : 100= 1*25+ 6*10+ 15
106=( 1, 7, 11) but : 100= 1*25+ 7*10+ 5
106=( 1, 8, 1) is good
106=( 2, 0, 56) but : 100= 2*25+ 0*10+ 50
106=( 2, 1, 46) but : 100= 2*25+ 1*10+ 40
106=( 2, 2, 36) but : 100= 2*25+ 2*10+ 30
106=( 2, 3, 26) but : 100= 2*25+ 3*10+ 20
106=( 2, 4, 16) but : 100= 2*25+ 4*10+ 10
106=( 2, 5, 6) but : 100= 2*25+ 5*10+ 0
106=( 3, 0, 31) but : 100= 3*25+ 0*10+ 25
106=( 3, 1, 21) but : 100= 3*25+ 1*10+ 15
106=( 3, 2, 11) but : 100= 3*25+ 2*10+ 5
106=( 3, 3, 1) is good
106=( 4, 0, 6) but : 100= 4*25+ 0*10+ 0






5 0
3 years ago
Given the matrices: 1 2 A= 1 -1 2 1 1 B= 3 4 Calculate AB: C11 C12 [2.1] х 1 2 3 4 C21 C22 C11 = C12 = -2 C22 - C215 DONE​
eduard

Answer:

\:c_{11}=-2,\:\:\:c_{12}=-2

\:c_{21}=5,\:\:\:c_{22}=8

Step-by-step explanation:

Given the matrices

A=\begin{pmatrix}1&-1\\ 2&1\end{pmatrix}

B=\begin{pmatrix}1&2\\ \:3&4\end{pmatrix}

Calculating AB:

\begin{pmatrix}1&-1\\ \:\:2&1\end{pmatrix}\times \:\begin{pmatrix}1&2\\ \:\:3&4\end{pmatrix}=\begin{pmatrix}c_{11}&c_{12}\\ \:\:\:c_{21}&c_{22}\end{pmatrix}

Multiply the rows of the first matrix by the columns of the second matrix

                                   =\begin{pmatrix}1\cdot \:1+\left(-1\right)\cdot \:3&1\cdot \:2+\left(-1\right)\cdot \:4\\ 2\cdot \:1+1\cdot \:3&2\cdot \:2+1\cdot \:4\end{pmatrix}

                                   =\begin{pmatrix}-2&-2\\ 5&8\end{pmatrix}

Hence,

\begin{pmatrix}c_{11}&c_{12}\\ \:\:\:c_{21}&c_{22}\end{pmatrix}=\begin{pmatrix}-2&-2\\ \:5&8\end{pmatrix}

Therefore,

\:c_{11}=-2,\:\:\:c_{12}=-2

\:c_{21}=5,\:\:\:c_{22}=8

5 0
3 years ago
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irina [24]
7*5*2=70 the total cost
7 0
3 years ago
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