By using Coulomb's law, we want to find the value of q₁ given that q₂ experiences no net electric force. We will find that q₁ = 8nC
<h3>Working with Coulomb's law.</h3>
Coulomb's law says that for two charges q₁ and q₂ separated by a distance r, the force that each one experiences is:
Where k is a constant
Here we can see that q₂ interacts with two charges, then the total force on q₂ will be:
And we know that it must be equal to zero, so we can write it as:
The parenthesis must be equal to zero, so we can write:
And now we can solve this for q₁ to get:
If you want to learn more about Coulomb's law, you can read:
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45 kg * 9.8 m/s^2 = <u>441 N.</u>
There is a relationship between the energy of a photon and its wavelength. This can be expressed as a mathematical equation shown below:
E = hc/λ
where
h is the Planck's constant equal to 6.62607004 × 10⁻³⁴ m²<span> kg / s
c is the speed of light equal to 3</span>× 10⁸ m/s
λ is the wavelength
3.5×10⁻¹⁶ J = (6.62607004 × 10⁻³⁴ m² kg / s)(3× 10⁸ m/s)/λ
Solving for λ,
λ = 56.8×10⁻⁹ m or<em> 56.8 nm</em>
Answer: The correct answer is option (C).
Explanation:
As it is given in the problem, the path of a meteor passing Earth is affected by its gravitational force and falls to Earth's surface. Another meteor of the same mass falls to Jupiter's surface due to its gravitational force.
According to Newton's law of universal gravitational, every particle attracts every other particles in the universe with the gravitational force which is directly proportional to the product of their masses and inversely proportional to the square of the distance between them.
The Jupiter is the most massive planet in the solar system. It is also the largest planet in the solar system. The gravity of Jupiter on its surface is 2.4 times that of surface gravity of the Earth.
If a person weighs 100 pounds on the Earth then he would weigh 240 pounds on Jupiter.
Therefore, the correct answer is option (C), the meteor falls to Jupiter faster due to its greater gravitational force.
Answer:410 Hz
Explanation:
It is given that frequency of tuning fork is 415 Hz and hears a beat of 5 beat per second
so untuned frequency must be either 410 Hz or 420 Hz because beat frequency is the difference in frequency of two notes.
When she tightens the string the beat frequency decrease
and velocity 
where 
where T=tension
it T increase v also increases and from 1 st equation frequency is also increasing therefore untuned frequency must be 410 Hz because beat frequency is decreasing.
