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Georgia [21]
2 years ago
9

100 POINTS!!!

Chemistry
1 answer:
mixas84 [53]2 years ago
4 0

1) Area of one side of each cube

The area of one side of each cube can be calculated by multiplying the length times the width:

A=L\cdot W

where

L = length

W = width

For cube A: L=1 cm, W=1 cm

So the area is: A_A = (1)(1)=1 cm^2

For cube B: L=2 cm, W=2 cm

So the area is: A_B=(2)(2)=4 cm^2

For cube C: L=3 cm, W=3 cm

So the area is: A_C=(3)(3)=9 cm^2

2) Surface area of each cube

The surface area of a cube is given by the sum of the areas of all its faces. Since a cube has 6 identical faces, this means that the total surface area is equal to 6 times the area of one face:

A=6 A_1

where

A_1 is the area of one face of the cube

For cube A, the area of one face is A_A=1 cm^2

So the surface area of cube A is

A'_A = 6A_A=6(1)=6 cm^2

For cube B, the area of one face is A_B=4 cm^2

So the surface area of cube B is

A'_B = 6A_B=6(4)=24 cm^2

For cube C, the area of one face is A_C=9 cm^2

So the surface area of cube C is

A'_C = 6A_C=6(9)=54 cm^2

3) Volume of each cube

The volume of a cube is obtained by multiplying its length, its width and its height:

V=L\cdot W \cdot H

Where:

L = length

W = width

H = height

Moreover for a cube, all the sides have equal length, so L=W=H

So the volume can be rewritten as

V=L^3

For cube A: L = 1 cm

So the volume is V_A=(1 cm)^3 = 1 cm^3

For cube B: L = 2 cm

So the volume is V_B=(2 cm)^3 = 8 cm^3

For cube C: L = 3 cm

So the volume is V_C = (3 cm)^3 = 27 cm^3

4) Ratio surface area/volume for each cube

In this part, we have to calculate the ratio between surface area and volume of each cube:

r=\frac{A}{V}

where

A is the surface area

V is the volume

For cube A, we have:

A_A = 6 cm ^2 (surface area)

V_A=1 cm^3 (volume)

So the ratio for cube A is:

r=\frac{6}{1}=6

For cube B, we have:

A_B = 24 cm ^2 (surface area)

V_B=8 cm^3 (volume)

So the ratio for cube B is:

r=\frac{24}{8}=3

For cube C, we have:

A_C = 54 cm ^2 (surface area)

V_C=27 cm^3 (volume)

So the ratio for cube C is:

r=\frac{54}{27}=2

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Explanation:

Step 1: Data given

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Step 2: The balanced equation

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For 2 moles octane we need 25 moles O2 to produce 16 moles CO2 and 18 moles H2O

O2 is the limiting reactant. It will completely be consumed. (3.28 moles). There will react 3.28 / 12.5 = 0.2624 moles. There will remain 0.639 - 0.2624  = 0.3766 moles octane

Step 5: Calculate mass octane remaining

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First of all, we set up an equilibrium expression for the given chemical equation at equilibrium, in which water is omitted for it is liquid and just aqueous species are allowed to be included:

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Next, we calculate the concentration of hydroxide ions and the Kb due to the fact that both the pH and pKb were given:

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Learn more:

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So, the final answer be come<em> </em>

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