Answer:
It is a linear function.
Step-by-step explanation:
The graph shows a straight line. Therefore the function must be linear. Unless you were asking about the equation of the line? Let me know.
To find the equation of this line, you would take the two points it passes through, (-3, 0) and (0, -2), and plug it into the slope formula, (y2-y1)/(x2-x1).
This would get you (-2 - 0)/ (0 - (-3)), which is -2/3.
Then, you can use slope intercept form to write the equation, since you have the y intercept already, (0, -2). Slope intercept is y=mx+b.
The line of the equation would then be y = -2/3x -2
Answer:
The signal would have experienced aliasing.
Step-by-step explanation:
Given that:
the bandwidth of the signal 
= 36MHz
= 36 × 10⁶ Hz
The sampling frequency 
= 36 × 10⁶ Hz
Suppose the sampling frequency is equivalent to the bandwidth of the signal, then aliasing will occur.
Therefore, according to the Nyquist criteria;
Nyquist criteria posit that if the sampling frequency is more above twice the maximum frequency to be sampled, a repeating waveform can be accurately reconstructed.
∴
By Nyquist criteria, for perfect reconstruction of an original signal, i.e. the received signal without aliasing effect;
Then,
∴
The signal would have experienced aliasing.
Answer:
k = 4
Step-by-step explanation:
7k - 6 = 2k + 14
(7k - 2k) - 6 = (2k - 2k) + 14
5k - 6 = 14
5k (- 6 + 6) = 14 + 6
5k = 20
5k/5 = 20/5
k = 4
The answer is the mean, mode, and median increases by 4, the range of times is the same.
Week 1: Week 2:
Student - Hours Student - Hours<span>
Bob 19 </span>Bob 23<span>
James 10 </span>James 14<span>
Karen 15 </span>Karen 19<span>
Rosario 17 </span>Rosario 21<span>
Antoine 10 </span>Antoine 14<span>
Julio 16 </span>Julio 20<span>
Maria 13 </span>Maria 17<span>
The mean is the sum of all values divided by the number of values:
Week 1: (19 + 10 + 15 + 17 + 10 + 16 + 13)/7 = 100/7 = 14.28
Week 2: (23 + 14 + 19 + 21 + 14 + 20 + 17)/7 = 128/7 = 18.28
The difference in means between Week 2 and Week 1 is 4 (18.28 - 14.28 = 4)
The median is the middle value. To calculate, first rearrange values from the lowest to the highest and then find the middle value:
Week 1: 10, 10, 13, 15, 16, 17, 19 - The median is 15.
Week 2: 14, 14, 17, 19, 20, 21, 23 - The median is 19.
The difference in medians between Week 2 and Week 1 is 4 (19 - 15 = 4)
The mode is the value that occurs most frequently.
</span>Week 1: 10, 10, 13, 15, 16, 17, 19 - The mode is 10.
Week 2: 14, 14, 17, 19, 20, 21, 23 - The mode is 14.
The difference in modes between Week 2 and Week 1 is 4 (14 - 10 = 4)
The range of times is the difference between the highest and the lowest value.
Week 1: 10, 10, 13, 15, 16, 17, 19 - The range of times is 9 (19 - 10 = 9).
Week 2: 14, 14, 17, 19, 20, 21, 23 - The median is 9 (23 - 14 = 9).
The difference in the ranges of times between Week 2 and Week 1 is 0 (9 - 9 = 0)
The argument is valid by the law of detachment.
