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3 years ago

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The area of a triangle is 30 m². Using the equation A=12bh A = 1 2 b h , where b is base and h is height, solve for h if b = 3 m

. Round to three decimal places, if necessary.

1 answer:

Mama L [17]3 years ago

8 0

Answer:

20 metres

Explanation:

Given that the area of a triangle is 30 square metres (m²). Using the equation A = 1/2bh, this is the formula for the triangle.

where b is base and h is height

Given that b = 3 metres.

To calculate h, Substitute b and A into the equation

30 = 1/2 × 3 × h

3h = 60

h = 60/3

h = 20 m

Therefore, h is equal to 20 metres

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An electron and a proton each have a thermal kinetic energy of 3kBT/2. Calculate the de Broglie wavelength of each particle at a

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Answer:

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Using eqn (2) in (1):

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$\lambda_{p} = \frac{h}{p_{p}}$

$\lambda_{p} = \frac{h}{m_{p}{v_{p}}$ (3)

where

$m_{p} = 1.6726\times 10_{- 27} kg$ = mass of proton

$v_{p}$ = velocity of an proton

Now,

Kinetic energy of a proton = thermal kinetic energy

$\frac{1}{2}m_{p}v_{p}^{2} = \frac{3}{2}k_{b}T$

$}v_{p} = \sqrt{2\frac{\frac{3}{2}k_{b}T}{m_{p}}}$

$}v_{p} = \sqrt{\frac{3\times 1.38\times 10^{- 23}\times 1800}{1.6726\times 10_{- 27}}}$

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$\lambda_{p} = \frac{6.626\times 10^{- 34}}{1.6726\times 10_{- 27}\times 6.674\times 10^{3}} = 5.94\times 10^{- 11} m = 0.0594 nm$

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