Answer:
You can drink 18 drinks and 1.38 dollars left with you.
Explanation:
1 drink cost 1.59 dollars
You have 30 dollars with you.
Number of drinks in 30 dollars =
Number of drinks in 30 dollars = 18
From division 1.36 remains as remainder so, 1.38 dollars left with you.
Answer:
8.27°
Explanation:
To angle difference will be determined by the difference in the displacement of the springs, produced by the weight of the center of mass of the rod.
by a simple trigonometric relation you obtain that the angle:
hence, the angle between the rod and the horizontal is 8.27°
The magnitude of the electric field just outside the surface of the sphere is
given:
radius,r=0.01m
charge,Q=1.0×10-9
what is electric field?
Electric field is defined as the electric force per unit charge.It is surrounded by electrically charged particles and exerts force on all other charge particles.
using formula,
for just outside r=radius of sphere
Thus,the electric field just outside the surface of the sphere is
learn more about electric field from here: brainly.com/question/28203588
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In order to lift the fat (306 lb) physics professor 89 meters up to
the rim, he'll need more potential energy, equal to
(mass) x (gravity) x (height) = (139 x 9.8 x 89) = 121,236 joules .
If the faithful horse delivers 1 constant horsepower = 746 watts,
AND if the cute-as-a-button student has instantly figured out a
way to keep the rope sliding around the edge without any friction,
then the soonest Prof. Tubby can arrive at the rim is
(121,236 joules) / (746 joules/sec) = 162.5 seconds .
Nowhere in this tense drama has the student needed her linguistics
skill yet, but I'll bet it comes in handy as she attempts gamely to
comprehend all of the various pleadings, prayers, and expletives
uttered by her heavy hero from the time he falls over the rim until
he's again lifted to it.
Answer:
2.7 J
Explanation:
From the question,
The Net work done by the crate = Work done by the crate in moving if through a distance- work done against friction.
W = Fd-F'd.................... Equation 1
Where F = force applied to the crate, d = distance moved by the crate, F' = force of friction
Given: F = 2.4 N, F' = 0.6 N, d = 1.5 m
Substitute these values into equation 1
W = 2.4(1.5)-0.6(1.5)
W = 3.6-0.9
W = 2.7 J