Correct answer is letter B. sandstone
Proton positive; electron negative; neutron no charge<span>. </span>The charge<span> on the proton and </span>electron<span> are exactly the same size but opposite. The same number of protons and </span>electrons<span> exactly cancel one another in a neutral atom.
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hoped it helped
Answer:
the frequency of this mode of vibration is 138.87 Hz
Explanation:
Given;
length of the copper wire, L = 1 m
mass per unit length of the copper wire, μ = 0.0014 kg/m
tension on the wire, T = 27 N
number of segments, n = 2
The frequency of this mode of vibration is calculated as;
Therefore, the frequency of this mode of vibration is 138.87 Hz
If you take 50 meters and divide by 23.1 seconds, you will get 2.16 meters per second.
So his average speed is 2.16 m/s.