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nataly862011 [7]
3 years ago
10

Which family on the periodic table is least likely to enter into chemical reactions? 1 2 17 18

Chemistry
2 answers:
vekshin13 years ago
6 0
Elements present in group 18 are known as noble gases. The outermost shell of these elements are completely filled.

18 is the answer
finlep [7]3 years ago
5 0

Answer: Option (d) is the correct answer.

Explanation:

When an element has incompletely filled valence or outermost shell then that atom is most likely to undergo a chemical reaction in order to attain stability.

For example, sodium has atomic number 11 and its electronic configuration is 2, 8, 1. So, to attain stability sodium will readily loose 1 electron. Hence, it will become reactive in nature to attain stability.

Whereas argon has atomic number 18 and its electronic configuration is 2, 8, 8. Therefore, its valence shell is completely filled so, it will not react easily.

Hence, we can conclude that family of group 18 on the periodic table is least likely to enter into chemical reactions.

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A Weather Satellite. 
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2 years ago
Define Acid dissociation constant constant
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Answer:

An acid dissociation constant, K a, (also known as acidity constant, or acid-ionization constant) is a quantitative measure of the strength of an acid in solution. It is the equilibrium constant for a chemical reaction ↽ − − ⇀ − + + known as dissociation in the context of acid–base reactions.

Explanation:

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3 years ago
How many moles are present in 2.45 x 1023 molecules of CH ?
Phantasy [73]

Answer:

the aware is 6182

Explanation:

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4 0
3 years ago
50 Points for whoever does it and shows their work. Maya has four glasses of milk. The temperature and the amount of milk in eac
galina1969 [7]

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A. 20 grams of milk at 10°C

Explanation:

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3 0
3 years ago
Read 2 more answers
Suppose you have just added 200.0 ml of a solution containing 0.5000 moles of acetic acid per liter to 100.0 ml of 0.5000 M NaOH
uranmaximum [27]

Answer:

The final pH is 3.80

Explanation:

Step 1: Data given

Volume of acetic acid = 200.0 mL = 0.200 L

Number of moles acetic acid = 0.5000 moles

Volume of NaOH = 100.0 mL = 0.100 L

Molarity of NaOH = 0.500 M

Ka of acetic acid = 1.770 * 10^-5

Step 2: The balanced equation

CH3COOH + NaOH → CH3COONa + H2O

Step 3: Calculate moles

moles = molarity * volume

Moles NaOH = 0.500 M * 0.100 L

Moles NaOH = 0.0500 moles

Step 4: Calculate the limiting reactant

For 1 mol CH3COOH we need 1 mol NaOH to produce 1 mol CH3COONa and 2 moles H2O

NaOH is the limiting reactant. It will completely be consumed (0.0500 moles). CH3COOH is in excess. There will react 0.0500 moles . There will remain 0.500 - 0.0500 = 0.450 moles

There will be produced 0.0500 moles CH3COONa

Step 5: Calculate the total volume

Total volume = 200.0 mL + 100.0 mL = 300.0 mL

Total volume = 0.300 L

Step 6: Calculate molarity

Molarity = moles / volume

[CH3COOH] = 0.450 moles / 0.300 L

[CH3COOH] = 1.5 M

[CH3COONa] = 0.0500 moles / 0.300 L

[CH3COONa]= 0.167 M

Step 7: Calculate pH

pH = pKa + log[A-]/ [HA]

pH = -log(1.77*10^-5) + log (0.167/ 1.5)

pH = 4.75 + log (0.167/1.5)

pH = 3.80

The final pH is 3.80

7 0
3 years ago
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