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liubo4ka [24]
3 years ago
11

A loop of area 0.0633 m^2 is oriented perpendicular (0 deg) to a magnetic field. The magnetic field changes in strength from 0.8

94 T to 2.28 T. How much does the magnetic flux CHANGE as a result?
Physics
1 answer:
frez [133]3 years ago
8 0

Answer:

The magnetic flux change is 0.0877 Wb.

Explanation:

Given that,

Area = 0.0633 m²

Angle = 0°

Magnetic field changes

B_{1}=0.894\ T

B_{2}=2.28\ T

We need to calculate the magnetic flux change

Using formula of flux

\Delta \phi=BA\cos\theta

\Delta \phi=A(B_{f}-B_{i})\cos\theta

Where, B = magnetic field

A = area

Put the value into the formula

\Delta \phi =0.0633\times(2.28-0.894)

\Delta \phi=0.0877\ Wb

Hence, The magnetic flux change is 0.0877 Wb.

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Given:

mass of object = 50kg

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