The net force acting on the crate is determined as 176 N to the left.
<h3>Net force acting on the crate</h3>
The net force acting on the crate is calculated as follows;
∑F = F1 + F2 + F3 + F4
F(net) = -440y + 176x + 440y - 352x
F(net) = -176 x
The resultant force is pointing in negative x direction.
Thus, the net force acting on the crate is determined as 176 N to the left.
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The correct option is C) The angle between the vectors is 120°.
Why?
We can solve the problem and find the correct option using the Law of Cosine.
Let A and B, the given two sides and R the resultant (sum),
Then,

So, using the law of cosines, we have:

Hence, we have that the angle between the vectors is 120°. The correct option is C) The angle between the vectors is 120°
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Answer:
v = 8.57 m/s
Explanation:
As we know that the wagon is pulled up by string system
So the net force on the wagon along the inclined is due to tension in the rope and component of weight along the inclined plane
So as per work energy theorem we know that
work done by tension force + work done by force of gravity = change in kinetic energy

so we have


m = 38.2 kg
d = 85.4 m
so now we have


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Answer:
Capacitance, C = 26.1 picofarad
Explanation:
It is given that,
Side of square, x = 4.3546 cm = 0.043546 m
Distance between electrodes, d = 0.6408 mm = 0.0006408 m
Voltage, V = 73.68 V
Capacitance of parallel plates is given by :



or
C = 26.1 picofarad
So, the capacitance of the capacitor is 26.1 picofarad. Hence, this is the required solution.