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3 years ago

Running a 5k would be an example of a good short-term goal for someone who is just starting out running.

Physics

2 answers:

tatiyna3 years ago

6 0

Answer:

Whats the question?

Explanation:

katen-ka-za [31]3 years ago

6 0

If this is a true or false I would say false

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What should we do to be a computer engineer ‍ ‍?

ycow [4]

Answer:

to be an eginere u would have to go to college and study hard

Explanation:

6 0

3 years ago

Read 2 more answers

In attempting to pass the puck to a teammate, a hockey player gives it an initial speed of 2.8 m/s. However, this speed is inade

erastova [34]

Answer:

3.95979 m/s

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

$v^2-u^2=2as\\\Rightarrow as=\frac{v^2-u^2}{2}\\\Rightarrow as=\frac{0^2-2.8^2}{2}\\\Rightarrow as=-3.92$

Here $s=\frac{1}{2}s$

$\\\Rightarrow as=-7.84\ m/s^2$

$v^2-u^2=2as\\\Rightarrow -u^2=2as-v^2\\\Rightarrow u=\sqrt{v^2-2as}\\\Rightarrow u=\sqrt{0^2-2\times -7.84}\\\Rightarrow u=3.95979\ m/s$

Initial velocity of the puck should be 3.95979 m/s

8 0

3 years ago

The current in an electric hair dryer is 10

Vikki [24]

First let's convert the time in seconds:
$\Delta t= 5 min= 5 min \cdot (60 s/min)= 300 s$

The current is defined as the quantity of charge flowing through a certain section of a circuit per unit of time:
$I= \frac{Q}{\Delta t}$
Using I=10 A, and $\Delta t=300 s$ , we can find the amount of charge flown through the hair dryer in this time:
$Q=I \Delta t=(10 A)(300 s)=3000 C$

The charge of a single electron is $q=1.6 \cdot 10^{-19} C$ , so the number of electrons flown through the hair dryer is the total charge divided by the charge of a single electron:
$N= \frac{Q}{q}= \frac{3000 C}{1.6 \cdot 10^{-19} C} =1.88 \cdot 10^{22}$

8 0

4 years ago

Two protons move at speed v, one along the x axis and one along the y axis. What is the relative speed of the two protons? Evalu

forsale [732]

Answer:

0.85 c

Explanation:

When the two travel at right angles to each other , their relative velocity is given by the hypotenuse formed by the x and y direction velocities.

Relative velocity of the two protons is given as

$\sqrt{v^{2}+v^{2}} = (\sqrt{2} ) v$