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3 years ago

Which of these compounds would be the best

1 answer:

Volgvan3 years ago

6 0

Answer: 6. Rb Cl

Because, as the electronegativities of the elements, Rb and Cl, indicate this an ionic compound. Meaning that the elements are as ions ( Rb+ Cl-)., which in liquid (molten) state are charges that move freely, making the compound a good conductor of electricity.

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for: rate=k[A]^x determine the value of x if the rate doubles when [A] is doubled; and if the rate quadruples when [A] is double

Rom4ik [11]

1. The value of x if the rate doubles when [A] is doubled is that x = 1

2. Then if the rate quadruples when [A] is doubled is that x= 2
Since x=1 when the rate doubles, so if it quadruples, it will be times 2.
So the solution to this is 1 times 2= 2
x=2

5 0

4 years ago

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solution of a weak acid HA has initial concentration c and acid ionization constant Ka. To what concentration should the acid be

soldier1979 [14.2K]

Answer:

The concentration c is equal to Ka

Explanation:

The acid will ionize as observed in the following reaction:

HA = H+ + A-

H+ is the proton of the acid and A- is the conjugate base . The equation to calculate the Ka is as follows:

Ka = ([H+]*[A -])/[HA]

Initially we have to:

[H+] = 0

[A-] = 0

[HA] = c

During the change we have:

[H+] = +x

[A-] = +x

[HA] = -x

During balance we have:

[H+] = 0 + x

[A-] = 0 + x

[HA] = c - x

Substituting the Ka equation we have:

Ka = ([H+]*[A-])/[HA]

Ka = (x * x)/(c-x)

x^2 + Kax - (c * Ka) = 0

We must find c, having as [H+] = 1/2c. Replacing we have:

(1/2c)^2 + (Ka * 1/2 * c) - (c * Ka) = 0

(c^2)/2 + Ka(c / 2 - c) = 0

(c^2)/2 + (-Ka * c/2) = 0

c^2 -(c*Ka) = 0

c-Ka = 0

Ka = c

8 0

3 years ago

Aqueous sulfuric acid reacts with solid sodium hydroxide to produce aqueous sodium sulfate and liquid water . If of water is pro

sergeinik [125]

The question is incomplete, here is the complete question:

Aqueous sulfuric acid reacts with solid sodium hydroxide to produce aqueous sodium sulfate and liquid water. If 12.5 g of water is produced from the reaction of 72.6 g of sulfuric acid and 77.0 g of sodium hydroxide, calculate the percent yield of water. Be sure your answer has the correct number of significant digits in it.

Answer: The percent yield of water in the reaction is 46.85 %.

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

For NaOH:

Given mass of NaOH = 77.0 g

Molar mass of NaOH = 40 g/mol

Putting values in equation 1, we get:

$\text{Moles of NaOH}=\frac{77.0g}{40g/mol}=1.925mol$

For sulfuric acid:

Given mass of sulfuric acid = 72.6 g

Molar mass of sulfuric acid = 98 g/mol

Putting values in equation 1, we get:

$\text{Moles of sulfuric acid}=\frac{72.6g}{98g/mol}=0.741mol$

The chemical equation for the reaction of NaOH and sulfuric acid follows:

$H_2SO_4+2NaOH\rightarrow Na_2SO_4+2H_2O$

By Stoichiometry of the reaction:

1 mole of sulfuric acid reacts with 2 moles of NaOH

So, 0.741 moles of sulfuric acid will react with = $\frac{2}{1}\times 0.741=1.482mol$ of NaOH

As, given amount of NaOH is more than the required amount. So, it is considered as an excess reagent.

Thus, sulfuric acid is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

1 mole of sulfuric acid produces 2 moles of water

So, 0.741 moles of sulfuric acid will produce = $\frac{2}{1}\times 0.741=1.482moles$ of water

Now, calculating the mass of water from equation 1, we get:

Molar mass of water = 18 g/mol

Moles of water = 1.482 moles

Putting values in equation 1, we get:

$1.482mol=\frac{\text{Mass of water}}{18g/mol}\\\\\text{Mass of water}=(1.482mol\times 18g/mol)=26.68g$

To calculate the percentage yield of water, we use the equation:

$\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100$

Experimental yield of water = 12.5 g

Theoretical yield of water = 26.68 g

Putting values in above equation, we get:

$\%\text{ yield of water}=\frac{12.5g}{26.68g}\times 100\\\\\% \text{yield of water}=46.85\%$

Hence, the percent yield of water in the reaction is 46.85 %.

8 0

3 years ago

A soccer player kicks a soccer ball. The ball travels 20 meters before landing on the ground. The ball stayed in the air for 5 s

natulia [17]

Answer:

4 meters per second

Explanation:

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3 years ago

Which ecological relationship is best represented by this graph?

olga55 [171]

Explanation:

Number 1 and 2, Are good things.

if one is decreasing and the other is benefiting. Otherwise, Here as number 3.

7 0

3 years ago

Read 2 more answers