Answer:
D. 108 grams of KNO3(Potassium nitrate)
Answer:
2Ag(s) + 1H2S(g) → 1Ag2S(s) + 1H2(g)
Explanation:
Step 1: Data given
Ag(s) + H2S(g) → Ag,S(s) + H2(g)
Ag has and oxidation number of +1
S has an oxidation number of -2
H has an oxidation number of +1
Step 2: The balanced equation
Ag+ + 2H+ + S^2- →
The silver ion and the sulfur ion will bind, but we need 2 silver atoms to bind with 1 sulfur atom.
2 H- atoms will appear as H2.
The balanced equation is:
2Ag+ + 2H+ +S^2- → Ag2S + H2
2Ag(s) + 1H2S(g) → 1Ag2S(s) + 1H2(g)
Answer:
Aluminum lodide - 680 degrees
fructose- 824 degrees
potassium bromide- 2,615 degrees
calcium bromide 3, 515 degrees
lowest boiling point is 680 and highest is 3,515.
hope this helps:)
