Answer:
![m_{solute}=100g](https://tex.z-dn.net/?f=m_%7Bsolute%7D%3D100g)
Explanation:
Hello,
In this case, by considering the mathematical definition of by mass percentage of a solute as shown below:
![\%m/m=\frac{m_{solute}}{m_{solution}}*100\%](https://tex.z-dn.net/?f=%5C%25m%2Fm%3D%5Cfrac%7Bm_%7Bsolute%7D%7D%7Bm_%7Bsolution%7D%7D%2A100%5C%25)
We are able to compute the mass of the solute in a 20% solution having 500 g of solution as follows:
![m_{solute}=\frac{m_{solution}*\%m/m}{100\%} =\frac{500g*20\%}{100\%}\\ \\m_{solute}=100g](https://tex.z-dn.net/?f=m_%7Bsolute%7D%3D%5Cfrac%7Bm_%7Bsolution%7D%2A%5C%25m%2Fm%7D%7B100%5C%25%7D%20%3D%5Cfrac%7B500g%2A20%5C%25%7D%7B100%5C%25%7D%5C%5C%20%5C%5Cm_%7Bsolute%7D%3D100g)
Best regards.
M₁=6.584 g
m₂=4,194 g
m(H₂O)=m₁-m₂
w(H₂O)=m(H₂O)/m₁
w(H₂O)=(m₁-m₂)/m₁
w(H₂O)=(6.584-4.194)/6.584=0.3630 (36.30%)
the percentage by mass of water in the hydrate 36.30
Answer:
In engineering and science the common stand is two places.
For example if you get a calculation of 4.567 round up and give the result of 4.57
Answer:
Mass in kg = 4.7*10^19 kg
Mass in tons = 5.2*10^16 tons
Explanation:
<u>Given:</u>
Total volume of sea water = 1.5*10^21 L
Mass % NaCl in seawater = 3.1%
Density of seawater = 1.03 g/ml
<u>To determine:</u>
Total mass of NaCl in kg and in tons
<u>Calculation:</u>
Unit conversion:
1 L = 1000 ml
The volume of seawater in ml is:
![=\frac{1.5*10^{21}L*1000ml }{1L} =1.5*10^{24} ml](https://tex.z-dn.net/?f=%3D%5Cfrac%7B1.5%2A10%5E%7B21%7DL%2A1000ml%20%7D%7B1L%7D%20%3D1.5%2A10%5E%7B24%7D%20ml)
![Mass\ seawater = Density*volume = 1.03g/ml*1.5*10^{24} ml=1.5*10^{24}g](https://tex.z-dn.net/?f=Mass%5C%20seawater%20%3D%20Density%2Avolume%20%3D%201.03g%2Fml%2A1.5%2A10%5E%7B24%7D%20ml%3D1.5%2A10%5E%7B24%7Dg)
![Mass\ NaCl\ in\ seawater = \frac{3.1}{100}*1.5*10^{24} g=4.7*10^{22} g](https://tex.z-dn.net/?f=Mass%5C%20NaCl%5C%20in%5C%20seawater%20%3D%20%5Cfrac%7B3.1%7D%7B100%7D%2A1.5%2A10%5E%7B24%7D%20%20g%3D4.7%2A10%5E%7B22%7D%20g)
To convert mass from g to Kg:
1000 g = 1 kg
![Mass\ seawater(kg) = \frac{4.7*10^{22}g*1kg }{1000g} =4.7*10^{19} kg](https://tex.z-dn.net/?f=Mass%5C%20seawater%28kg%29%20%3D%20%5Cfrac%7B4.7%2A10%5E%7B22%7Dg%2A1kg%20%7D%7B1000g%7D%20%3D4.7%2A10%5E%7B19%7D%20kg)
To convert mass from g to tons:
1 ton = 9.072*10^6 g
![Mass\ seawater(tons) = \frac{4.7*10^{22}g*1ton }{9.072*10^{6}g } =5.2*10^{16} tons](https://tex.z-dn.net/?f=Mass%5C%20seawater%28tons%29%20%3D%20%5Cfrac%7B4.7%2A10%5E%7B22%7Dg%2A1ton%20%7D%7B9.072%2A10%5E%7B6%7Dg%20%7D%20%3D5.2%2A10%5E%7B16%7D%20tons)
Answer: Water becomes gas at D-E.
Explanation:
In the flat line D-E water is absorbing energy to become gas, and when the water is completely gas, the temperature will increase again therefore the line will rise up.