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andrew-mc [135]
3 years ago
14

which of the following can best help you in a risky situation? stay close to the quieter kids have an excuse ready so you can le

ave hang around but don't participate participate only a little to stay safe
Physics
2 answers:
monitta3 years ago
8 0

Answer: Option (b) is the correct answer.

Explanation:

A risky situation is a situation in which there is no idea what the consequence would be as there might be a loss, injury or gain of something. So, basically a risky situation is not predictable.

For example, Ravi didn't attended Juhi's birthday party and when Juhi asked him the reason then Ravi made an excuse that he was out of station at that time due to some office work.

Therefore, we can conclude that out of the given options, have an excuse ready so you can leave best help you in a risky situation.

lesya692 [45]3 years ago
3 0
Have an excuse ready so you can leave 
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What happens to the wavelength of a wave if you increase the frequency?
dezoksy [38]

The product of (wavelength) times (frequency) is always the same number ...
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4 0
3 years ago
The x vector component of a displacement vector has a magnitude of 86.2 m and points along the negative x axis. The y vector com
Flauer [41]

Answer:

(a) Magnitude of Vector = 207.73 m

(b) Direction = 65.48°

Explanation:

(a)

The formula to find out the magnitude of a resultant vector with the help of its x and y components is given as follows:

Magnitude\ of\ Vector = \sqrt{d_{x}^{2} + d_{y}^{2}} = \sqrt{(86.2\ m)^{2} + (189\ m)^{2}}\\\\

<u>Magnitude of Vector = 207.73 m</u>

(b)

For the direction of the vector we have the formula:

Direction = tan^{-1}(\frac{y}{x})\\\\Direction = tan^{-1}(\frac{189\ m}{86.2\ m})\\\\

<u>Direction = 65.48°</u>

4 0
3 years ago
You are the juror of a case involving a drunken driver whose 1041 kg sports car ran into a stationary 1928 kg station wagon stop
mina [271]
1. Find the force of friction between the sports car and the station wagon stuck together and the road. The total mass m = 1928kg + 1041kg = 2969kg. The only force in the x-direction is friction: F = μ*N = μ * m * g 
2. Find the acceleration due to friction: 
F = m*a =  μ * m * g => a = μ * g = 0.6 * 9.81
3. Find the time it took the two cars stuck together to slide 12m:
x = 0.5*a*t² 
t = sqrt(2*x / a) = sqrt(2 * x / (μ * g) )
4. Find the initial velocity of the two cars:
v = a*t = μ * g * sqrt(2 * x / (μ * g) ) = sqrt( 2 * x * μ * g)
5. Use the initial velocity of the two cars combined to find the velocity of the sports car. Momentum must be conserved:

m₁ mass of sports car
v₁ velocity of sports car before the crash
m₂ mass of station wagon
v₂ velocity of station wagon before the crash = 0
v velocity after the crash

m₁*v₁ + m₂*v₂ = (m₁+m₂) * v = m₁*v₁ 
v₁ = (m₁+m₂) * v / m₁ = (m₁+m₂) * sqrt( 2 * x * μ * g) / m₁
v₁ = 33.9 m/s


7 0
3 years ago
You add 50 mL of water at 20C to 200 mL of water at 70C. What is the most likely final temperature of the mixture?
Veseljchak [2.6K]
100*20 + 200*80 = 300* T
T = 60
5 0
3 years ago
Read 2 more answers
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