A 9.0-kg bowling ball on a horizontal, frictionless surface experiences a net force of 6.0 n. what will be its acceleration?
1 answer:
This question involves the concepts of Newton's Second Law of Motion.
The acceleration of the bowling ball will be "0.67 m/s²".
<h3>Newton's Second Law of Motion</h3>According to Newton's Second Law of Motion, when an unbalanced force is applied on an object, it produces an acceleration in it, in the direction of the applied force. This acceleration is directly proportional to the force applied and inversely proportional to the mass of the object. Mathematically,
where,
- a = acceleration = ?
- F = Magnitude of the applied force = 6 N
- m = Mass of the ball = 9 kg
Therefore,
a = 0.67 m/s²
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Recall this gas law:
=
P₁ and P₂ are the initial and final pressures.
V₁ and V₂ are the initial and final volumes.
T₁ and T₂ are the initial and final temperatures.
Given values:
P₁ = 475kPa
V₁ = 4m³, V₂ = 6.5m³
T₁ = 290K, T₂ = 277K
Substitute the terms in the equation with the given values and solve for Pf:
Answer:
(a). Index of refraction are = 1.344 &
= 1.406
(b). The velocity of red light in the glass 2.23 ×
The velocity of violet light in the glass 2.13 ×
Explanation:
We know that
Law of reflection is
Here
= angle of incidence
= angle of refraction
(a). For red light
1 × =
×
= 1.344
For violet light
1 × =
×
= 1.406
(b). Index of refraction is given by
= 1.344
2.23 ×
This is the velocity of red light in the glass.
The velocity of violet light in the glass is given by
2.13 ×
This is the velocity of violet light in the glass.