Internal,covert processes
Answer:
0.785 m/s
Explanation:
Hi!
To solve this problem we will use the equation of motion of the harmonic oscillator, <em>i.e.</em>
- (1)
- (1)
The problem say us that the spring is released from rest when the spring is stretched by 0.100 m, this condition is given as:
Since cos(0)=1 and sin(0) = 0:
We get
Now it say that after 0.4s the weigth reaches zero speed. This will happen when the sping shrinks by 0.100. This condition is written as:
Since
This is the same as:
We know that cosine equals to -1 when its argument is equal to:
(2n+1)π
With n an integer
The first time should happen when n=0
Therefore:
π = 0.4ω
or
ω = π/0.4 -- (2)
Now, the maximum speed will be reached when the potential energy is zero, <em>i.e. </em>when the sping is not stretched, that is when x = 0
With this info we will know at what time it happens:
The first time that the cosine is equal to zero is when its argument is equal to π/2
<em>i.e.</em>
And the velocity at that time is:
But sin(π/2) = 1.
Therefore, using eq(2):
And so:
Answer:
Explanation:
Newton's First law of motion: An object is in motion, it remains in motion or an object is at rest it remains at rest until and unless an external force is not applied on the body.
For example, a car is at rest, it remains at rest as there is no external force is applied on the body.
Newton's Second law of motion: The rate of change of momentum of the object is directly proportional to the force applied on the object.
Force proportional to the rate of change in momentum.
Newton's Third law of motion: For every action, there is an equal and opposite reaction.
Action and reaction force acting on two different bodies.
Answer:
the acceleration is 2.5 MPH over 12 mins.
Explanation:
30 MPH in 12 minutes=
30/12=
2.5