La velocidad del buzo es de 7.04 m/s, 8.84 m/s y 2.27 m/s respectivamente.
<h3 /><h3>Velocidad
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La velocidad es la relación entre la distancia total recorrida y el tiempo total empleado. Está dado por:
Velocidad = distancia/tiempo
Para 10m de altura:
- Velocidad = 10 m/1.42 s = 7.04 m/s
Para 3m de altura:
- Velocidad = 3 m/0.78 s = 3.84 m/s
Para 1m de altura:
- Velocidad = 1 m/0.44 s = 2.27 m/s
La velocidad del buzo es de 7.04 m/s, 8.84 m/s y 2.27 m/s respectivamente.
Obtenga más información sobre la velocidad en: brainly.com/question/4931057
Answer:
The man moves across the ice with a speed of 0.345m/s.
Explanation:
From the conservation of linear momentum, we have that the total linear momentum before the book throw is equal to the total linear momentum just after it. Since the initial velocity of the system is zero (so the initial momentum is zero), we have that:
Where 
is the mass of the man, 
is the mass of the book, and 
and 
are their velocities. Plugging in the given values, we can compute the speed of the man (ignoring the negative sign, because we care about the magnitude, not the direction):
In words, the resulting speed of the man is 0.345m/s.
Answer:
The speed of the cart and clay after the collision is 50 cm/s .
Explanation:
Given :
Mass of lump , m = 500 g = 0.5 kg .
Velocity of lump , v = 30 cm/s .
Mass of cart , M = 1 kg .
Velocity of cart , V = 60 cm/s .
We know by conservation of momentum :
Here , 
is the speed of the cart and clay after the collision .
Putting all value in above equation .
We get :
Hence , this is the required solution .
I don’t think I’m right but I want to say 500 m/s
Answer:
The first graph is showing the constant acceleration (1 m/s)
Explanation:
The second graph showing the flexible velocity therefore a in the graph is different at t1, t2, t3, t4
The last graph is showing constant velocity therefore there is no acceleration (a = 0)
