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3 years ago

What would happen if they had no sunlight???

Chemistry

2 answers:

Sedbober [7]3 years ago

6 0

If they had no sunlight the whole food chain would be thrown off the produce would not grow giving the primary consumer nothing to eat then that and if they have no food they won’t survive and if that were to happen then the secondary consumer would have nothing to eat and it goes on and on for the rest of the chain.

Firdavs [7]3 years ago

4 0

Answer plants will die and with out plants we will die

Explanation:

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A change in matter that produces one or more new substances is a ???

Dvinal [7]

Chemical reaction, generally speaking. It's a vague definition, but it's easy to remember.

8 0

3 years ago

Read 2 more answers

What volume would a sample of gas occupy in LITERS at 0.985 atmospheres and a volume of 3.65 liters if the pressure were raised

musickatia [10]

Answer:

3.18 L

Explanation:

Step 1: Given data

Initial pressure (P₁): 0.985 atm

Initial volume (V₁): 3.65 L

Final pressure (P₂): 861.0 mmHg

Final volume (V₂): ?

Step 2: Convert P₁ to mmHg

We will use the conversion factor 1 atm = 760 mmHg.

0.985 atm × 760 mmHg/1 atm = 749 mmHg

Step 3: Calculate the final volume of the gas

Assuming ideal behavior and constant temperature, we can calculate the final volume using Boyle's law.

P₁ × V₁ = P₂ × V₂

V₂ = P₁ × V₁/P₂

V₂ = 749 mmHg × 3.65 L/861.0 mmHg = 3.18 L

7 0

2 years ago

What is the element 3O2 name

bija089 [108]

Answer:

Triplet oxygen

Explanation:

Based on my research it is called Triplet Oxygen, if this is wrong I'm sorry

5 0

3 years ago

Fill in the left side of this equilibrium constant equation for the reaction of benzoic acid (HC_6H_5CO_2) with water.

il63 [147K]

Answer:

[C₆H₅COO⁻][H₃O⁺]/[C₆H₅COOH] = Ka

Explanation:

The reaction of dissociation of the benzoic acid in water is given by the following equation:

C₆H₅-COOH + H₂O ⇄ C₆H₅-COO⁻ + H₃O⁺ (1)

The dissociation constant of an acid is the measure of the strength of an acid:

HA ⇄ A⁻ + H⁺ (2)

$K_{a} = \frac{[A^{-}][H^{+}]}{[HA]}$ (3)

<em>Where the dissociation constant of the acid (Ka) is equal to the ratio of the concentration of the dissociated forms of the acid, [A⁻][H⁺], and the concentration of the acid, [HA]. </em>

So, starting from the equations (2) and (3), the constant equation for the dissociation reaction of benzoic acid in water, of the equation (1), is:

$K_{a} = \frac{[C_{6}H_{5}COO^{-}][H_{3}O^{+}]}{[C_{6}H_{5}COOH]}$

I hope it helps you!

6 0

3 years ago

Q 9 The table lists the steps to clean water for drinking purpose. 1. Adding chlorine tablets to the water.2. Pouring the water

love history [14]

Answer:

1 and 2

Explanation:

when we r adding chlorine to water

the water is clean

8 0

2 years ago