Answer:
Part A = The mass of sulfur is 6.228 grams
Part B = The mass of 1 silver atom is 1.79 * 10^-22 grams
Explanation:
Part A
Step 1: Data given
A mixture of carbon and sulfur has a mass of 9.0 g
Mass of the product = 27.1 grams
X = mass carbon
Y = mass sulfur
x + y = 9.0 grams
x = 9.0 - y
x(molar mass CO2/atomic mass C) + y(molar mass SO2/atomic mass S) = 22.6
(9 - y)*(44.01/12.01) + y(64.07/32.07)
(9-y)(3.664) + y(1.998)
32.976 - 3.664y + 1.998y = 22.6
-1.666y = -10.376
y = 6.228 = mass sulfur
x = 9.0 - 6.228 = 2.772 grams = mass C
The mass of sulfur is 6.228 grams
Part B
Calculate the mass, in grams, of a single silver atom (mAg = 107.87 amu ).
Calculate moles of 1 silver atom
Moles = 1/ 6.022*10^23
Moles = 1.66*10^-24 moles
Mass = moles * molar mass
Mass = 1.66*10 ^-24 moles *107.87
Mass = 1.79 * 10^-22 grams
The mass of 1 silver atom is 1.79 * 10^-22 grams
A) cesium chloride
B) barium oxide
C) potassium sulfide
D) beryllium chloride
E) hydrogen bromide
F) aluminum fluoride
I acually habe no idea but I nust want to point out that my toast's brand is Sarah Lee lol
Answer:
0.54g of Cr
Explanation:
Current (I) = 10A
Time (t) = 100s
Molecular mass of Cr = 51.996 amu
Faraday's first law of electrolysis states that
The mass of the substance (m) of a given substance deposited at an electrode is directly proportional to the quantity of electricity or charge (Q) passed
m = nQ
M = mass of the substance
n = electrochemical constant
Q = charge passed through it
Q = IT
Q = (10 * 100) = 1000C
1 moles = molarmass = Faraday's constant (96500C)
Molar mass = Faraday's constant (96500C)
51.996 g = 96500C
How many grams will be liberated with 1000C
51.996g = 96500C
Xg = 1000C
X = (1000 * 51.996) / 96500
X = 51996 / 96500
X = 0.5388g = 0.54 g of Cr will be deposited
