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3 years ago

An atom's electrons have a great effect on

2 answers:

7 0

An atom's electrons have a great effect on how ''chemically reactive atom is".

An atom is a small particle that can exist or be combined with other atoms which forms a molecule. An atom is a chemical element.

Hope this helps :)

Dmitry [639]3 years ago

6 0

The correct answer is C. How chemically reactive the atom is.

Explanation:

An atom contains a nucleus with protons and neutrons as well as electrons negatively charged and bounded to the nucleus. Electrons do not affect the mass of the atom defined by the neutrons and protons, also they do not have and influence on the element the atom belongs to that is defined by protons but they affect magnetism and reactivity.

In terms of reactivity, this is mainly influenced by the number of electrons in the external shell of the atoms as this can form bonds with other atoms and therefore had a chemical reaction. Thus, an atom's electrons have a great effect on how chemically reactive the atom is.

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What is the relationship between the word pairs in this analogy? dull: boring as amusing: entertaining O A. Synonyms O B. Antony

leva [86]

Answer:

A: Synonyms

Explanation:

Synonyms are two words that have same meaning but are different words (tell me if this works!)

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3 years ago

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How many grams of NO can be made from 50 g of NH3?<br><br> 4 NH3 + 5 O2 → 6 H2O + 4 NO

Evgen [1.6K]

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2 years ago

Write the half-reactions as they occur at each electrode and the net cell reaction for this electrochemical cell containing indi

AlexFokin [52]

Explanation:

The given cell reaction is as follows.

$In(s)| In^{3+}(aq) || Cd^{2+}(aq) | Cd(s)$

Hence, reactions taking place at the cathode and anode are as follows.

At anode ; Oxidation-half reaction : $In(s) \rightarrow In^{3+}(aq) + 3e^{-}$ ...... (1)

At cathode; Reduction-half reaction : $Cd^{2+}(aq) + 2e^{-} \rightarrow Cd(s)$ ....... (2)

Hence, balance the half reactions by multiplying equation (1) by 2 and equation (2) by 3.

Therefore, net cell reaction is as follows.

$2In(s) \rightarrow 2In^{3+}(aq) + 6e^{-}$

$3Cd^{2+}(aq) + 6e^{-} \rightarrow 3Cd(s)$

Net reaction: $2In(s) + 3Cd^{2+}(aq) \rightarrow 2In^{3+}(aq) + 3Cd(s)$

Thus, we can conclude that the overall cell reaction is as follows.

$2In(s) + 3Cd^{2+}(aq) \rightarrow 2In^{3+}(aq) + 3Cd(s)$

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3 years ago

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2 years ago

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3 years ago