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liq [111]
2 years ago
8

The boiling point of another member of this homologous series was found to be 309 k. What is the likely molecular formula for th

is compound? Express your answer as a chemical formula.
Chemistry
1 answer:
Sati [7]2 years ago
3 0

Answer:

C5H12

Explanation:

In organic chemistry the boiling point of 309 k is of fifth member of alkane series which Pentane whose molecular mass is 72 g/mol.  Thus, we can say that the  molecular formula of the compound which has boiling point 309 K is C5H12.

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Which type of scientist would most likely study how electricity could be
miv72 [106K]

Answer:

A physicist

Explanation:

Physics is that aspect of science that deals with nature and matter in relation to energy. Electricity is a source for energy

7 0
2 years ago
An element has ccp packing with a face-centered cubic unit cell. its density is 8920 kg/m3 and the unit cell volume is 4.72 x 10
ziro4ka [17]
<span>63.4 g/mol
   First, let's determine how many atoms per unit cell in face-centered cubic. There is 8 corners, each of which has 1 atom, and each of those atoms is shared between 8 other unit cells. So 8*1/8 = 1 atom per unit cell. Additionally, there are 6 faces, each of which has 1 atom that's shared between 2 unit cells. So 6*1/2 = 3 atoms per unit cell. So each unit cell has the mass of 1+3 = 4 atoms. Since there is 1000 liters per cubic meter, the mass per liter is 8920 kg/1000 = 8.920 kg/L. Now the mass per unit cell is 8920 g * 4.72x10^-26 = 4.21024x10^-22 g per unit cell. The mass per atom is 4.21024x10^-22 g / 4 = 1.05256x10^-22 g/atom, Finally, multiply by Avogadro's number, getting 1.05256x10^-22 g/atom * 6.0221409x10^23 atom/mol = 63.38664625704 g/mol.
   Rounding to 3 significant digits gives 63.4 g/mol.</span>
5 0
3 years ago
There is a photon with a frequency of 8x10^12 Hz. What is the energy of this<br> photon?
jarptica [38.1K]

Answer:

33.085476 meV ≈ 33 meV

Explanation:

Hope this helped!

7 0
3 years ago
if you are told to get 100 mL of stock solution to use to prepare smaller size sample for an experiment, which piece of glasswar
fgiga [73]

Answer:

A beaker  

Step-by-step explanation:

Specifically, I would use a 250 mL graduated beaker.

A beaker is appropriate to measure 100 mL of stock solution, because it's easy to pour into itscwide mouth from a large stock bottle.

You don't need precisely 100 mL solution.

If the beaker is graduated, you can easily measure 100 mL of the stock solution.

Even if it isn't graduated, 100 mL is just under half the volume of the beaker, and that should be good enough for your purposes (you will be using more precise measuring tools during the experiment).

6 0
2 years ago
If the cylindrical pistons are 25.000 cm in diameter at 20.0 ∘c, what should be the minimum diameter of the cylinders at that te
attashe74 [19]
Refer to the diagram shown below.

The piston supports the same load W at both temperatures.
The ideal gas law is
pV=nRT
where
p = pressure
V = volume
n = moles
T = temperature
R = gas constant

State 1:
T₁ = 20 C = 20+273 = 293 K
d₁ = 25 cm piston diameter

State 2:
T₂ = 150 C = 423 K
d₂ = piston diameter

Because V, n, and R remain the same between the two temperatures, therefore
\frac{p_{1}}{T_{1}} = \frac{p_{2}}{T_{2}}

If the supported load is W kg, then
p_{1} =  \frac{W \, N}{ \frac{\pi}{4} d_{1}^{2}} = \frac{4W \, N}{\pi (0.25 \, m)^{2}} =  20.3718W \, Pa
Similarly,
p_{2} =  \frac{4W}{\pi d_{2}^{2}} \, Pa

\frac{p_{1}}{p_{2}} =  \frac{20.3718 \pi d_{2}^{2}}{4} = 16 d_{2}^{2}

Because p₁/p₂ = T₁/T₂, therefore
16d_{2}^{2} =  \frac{293}{423}  \\\\ d_{2}^{2} =  \frac{0.6927}{16}  \\\\ d_{2} = 0.2081 \, m

The minimum piston diameter at 150 C is 20.8 cm.

Answer: 20.8 cm diameter

8 0
3 years ago
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