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liq [111]
3 years ago
8

The boiling point of another member of this homologous series was found to be 309 k. What is the likely molecular formula for th

is compound? Express your answer as a chemical formula.
Chemistry
1 answer:
Sati [7]3 years ago
3 0

Answer:

C5H12

Explanation:

In organic chemistry the boiling point of 309 k is of fifth member of alkane series which Pentane whose molecular mass is 72 g/mol.  Thus, we can say that the  molecular formula of the compound which has boiling point 309 K is C5H12.

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Please help please ❤️❤️ !!
Lapatulllka [165]

Answer:

See attached picture!

Explanation:

There are two types of radioactive decay: alpha and beta.  

Alpha decay removes a helium atom from the original element, causing the original mass number to decrease by 4 and the original atomic number to decrease by 2.  

Beta decay removes an electron from the original element, causing the original mass number to remain the same and the original atomic number to increase by 1.

To solve your problems, you need to identify which decay is most likely to happen.  You could do this by checking the possible answer choices.  Usually, professors tell you which decay you are expected to write an equation of, but in this case, it's a matter of trial and error in order to get the answer.

6 0
3 years ago
6 + 9 = ? <br> This is a tough question, my fellow friends...
vesna_86 [32]

Answer:

uhmmmmmmmmmmmmmmmmm 15?

Explanation:

5 0
2 years ago
Read 2 more answers
Iridium has only two naturally occurring isotopes. The mass of iridium-191 is 190.9605 amu and the mass of iridium-193 is 192.96
cluponka [151]

Answer:

Abundance of Iridium-193 is 62.75%

Explanation:

From the question given above, the following data were obtained:

Isotope A (Iridium-191):

Mass of A = 190.9605 amu

Abundance of A = A%

Isotope B (Iridium-193):

Mass of B = 192.9629 amu

Abundance B = (100 – A) %

Relative atomic mass of Iridium = 192.217 amu

Next, we shall determine the abundance of isotope A (Iridium-191). This can be obtained as follow:

Relative atomic mass = [(Mass of A × A%)/100] + [(Mass of B × B%)/100]

192.217 = [(190.9605 × A%)/100] + [(192.9629 × (100 – A)%)/100]

192.217 = 1.909605A% + 1.929629(100 – A)%

192.217 = 1.909605A% + 192.9629 – 1.929629A%

Collect like terms

192.217 – 192.9629 = 1.909605A% – 1.929629A%

–0.7459 = –0.020024A%

Divide both side by –0.020024

A% = –0.7459 / –0.020024

A% = 37.25 %

Finally, we shall determine the abundance of Isotope B (Iridium-193).

This can be obtained as follow:

Abundance of A (Iridium-191) = 37.25 %

Abundance of B (Iridium-193) =?

Abundance B = 100 – A%

Abundance B = 100 – 37.25 %

Abundance of B (Iridium-193) = 62.75%

4 0
3 years ago
How many atoms of chlorine are in the carbon tetrachloride molecule?
zaharov [31]

Answer:

4 atoms of Chlorine

Explanation:

This is actually easy to explain,

First we have here a type of nomenclature. This one is the sistematic nomenclature, and begins by naming the number of atoms that one element has, beggining for the non metal first, and then the metal or the non metal acting like a metal. In this case, the Carbon is acting like a metal.

The number of atoms are named by a prefix of the number. Each number has a determined prefix. Here are some of them:

one = 1 = mono

two = 2 = bi or di

three = 3 = tri

Four = 4 = tetra

Five = 5 = penta

Six = 6 = Hexa

So tetrachloride, means that we have 4 atoms of chlorine in the molecule and the molecule is this one: CCl4

7 0
3 years ago
Read 2 more answers
Which of the following statements best describes the current atomic theory
blagie [28]
You did not provide possible answers, but one possible might be that the current atomic theory is so sound and plausible that there should not be anything that could change it in the near future.
3 0
3 years ago
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