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liq [111]
3 years ago
8

The boiling point of another member of this homologous series was found to be 309 k. What is the likely molecular formula for th

is compound? Express your answer as a chemical formula.
Chemistry
1 answer:
Sati [7]3 years ago
3 0

Answer:

C5H12

Explanation:

In organic chemistry the boiling point of 309 k is of fifth member of alkane series which Pentane whose molecular mass is 72 g/mol.  Thus, we can say that the  molecular formula of the compound which has boiling point 309 K is C5H12.

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1) Consider this row in the periodic table. What changes can you predict based on what information is provided by the boxes for
bearhunter [10]

Answer:

B) As you move across the row, the number of electrons increases and reactivity also increases.

Explanation:

The periodic table is arranged in a way that if you go across a period, the number of protons, neutrons, and electrons in an element increases. In terms of reactivity, the most reactive elements are the ones which have a high electronegativity. The electronegativity of the elements increases as you travel to the right and upwards on the periodic table.

4 0
2 years ago
The half-life of a strontium isotope is 25 years. How much of this particular isotope will remain after 100 years if the startin
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Answer:

1 gram

Explanation:

Half life = 25 years

Starting mass = 16 grams

Time = 100 years

Number of half lives = Time / Duration of Half life = 100 / 25 = 4

After first Half life;

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After Second Half life;

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After Third Half life;

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After Fourth Half life;

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3 years ago
An unknown amount of mercury (II) oxide was decomposed in the lab. Mercury metal was formed and 5.20 L of oxygen was released at
Yakvenalex [24]

Answer:

  • <u>68.3g</u>

Explanation:

<u>1. Word equation:</u>

  • <em>mercury(II) oxide → mercury + oxygen </em>

<u>2. Balanced molecular equation:</u>

  • 2HgO → 2Hg + O₂(g)

<u>3. Mole ratio</u>

Write the ratio of the coefficients of the substances that are object of the problem:

       2molHgO/1molO_2

<u>4. Calculate the number of moles of O₂(g)</u>

Use the equation for ideal gases:

          pV=nRT\\\\\\n=\dfrac{pV}{RT}\\\\\\n=\dfrac{0.970atm\times5.20L}{0.08206atm.L/K.mol\times 390.0K}\\\\\\n=0.1576mol

<u>5. Calculate the number of moles of HgO</u>

         \dfrac{2molHgO}{1molO_2}\times 0.1576molO_2=0.315molHgO

<u>6. Convert to mass</u>

  • mass = # moles × molar mass

  • molar mass of HgO: 216.591g/mol

  • mass = 0.315mol × 216.591g/mol = 68.3g

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