Answer:
The mean free path = 2.16*10^-6 m
Explanation:
<u>Given:</u>
Pressure of gas P = 100 kPa
Temperature T = 300 K
collision cross section, σ = 2.0*10^-20 m2
Boltzmann constant, k = 1.38*10^-23 J/K
<u>To determine:</u>
The mean free path, λ
<u>Calculation:</u>
The mean free path is related to the collision cross section by the following equation:
where n = number density
Substituting for P, k and T in equation (2) gives:
Next, substituting for n and σ in equation (1) gives:
Answer:
the chemical symbol is 96
Answer:
ponge is a solid yet we able to compress it because it has holes in it. When we compress the sponge the air goes out of those pores.
Explanation:
Answer:
T₂ = 169.89 K
Explanation:
Given data:
Initial volume = 250 cm³
Initial temperature = 10°C (10+273.15 K = 283.15 K)
Final temperature = ?
Final volume = 150 cm³
Solution:
The given problem will be solve through the Charles Law.
According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.
Mathematical expression:
V₁/T₁ = V₂/T₂
V₁ = Initial volume
T₁ = Initial temperature
V₂ = Final volume
T₂ = Final temperature
Now we will put the values in formula.
V₁/T₁ = V₂/T₂
T₂ = T₁V₂/V₁
T₂ = 283.15 K × 150 cm³ / 250 cm³
T₂ = 42472.5 K. cm³ / 250 cm³
T₂ = 169.89 K
