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vodomira [7]
3 years ago
15

Why is rusted iron an example of an oxidation-reduction reaction

Chemistry
2 answers:
stich3 [128]3 years ago
3 0
Electrons are exchanged.

hope i helped 

can i have branest 
DENIUS [597]3 years ago
3 0

<u>Answer:</u> Because electrons are getting transferred from iron to oxygen.

<u>Explanation:</u>

Oxidation-reduction reaction or redox reaction is defined as the reaction in which oxidation and reduction reaction occur simultaneously.

Oxidation reaction is defined as the reaction in which a substance looses its electrons. The oxidation state of the substance is increasing.

Reduction reaction is defined as the reaction in which a substance gain electrons. The oxidation state of the substance gets reduced.

For the reaction of rusting of iron, the equation follows:

4Fe(s)+3O_2(g)\rightarrow 2Fe_2O_3(s)

<u>On reactant side:</u>

Oxidation state of iron = 0

Oxidation state of Oxygen = 0

<u>On product side:</u>

Oxidation state of iron = +3

Oxidation state of Oxygen = -2

Half reactions of oxidation and reduction are:

Oxidation: Fe(s)\rightarrow Fe^{3+}+3e^-

Reduction: \frac{1}{2}O_2+2e^-\rightarrow O^{2-}

As, oxidation state of iron is increasing from 0 to +3, so it is getting oxidized and undergoes oxidation reaction. And, oxidation state of oxygen is getting decreased from ) to -2, so it is getting reduced and is considered as a reduction reaction.

Here, electrons are getting transferred from iron to oxygen. Hence, rusted of iron is an example of a redox reaction

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The solubility of two slightly soluble salts of M^2+ , MA and MZ_2, are the same, 4 x 10^â4 mol/L.
LekaFEV [45]

Answer:

a) MZ₂

b) They have the same concentration

c) 4x10⁻⁴ mol/L

Explanation:

a) The solubility (S) is the concentration of the salt that will be dissociated and form the ions in the solution, the solubility product constant (Kps) is the multiplication of the concentration of the ions elevated at their coefficients. The concentration of the ions depends on the stoichiometry and will be equivalent to S.

The salts solubilization reactions and their Kps values are:

MA(s) ⇄ M⁺²(aq) + A⁻²(aq) Kps = S*S = S²

MZ₂(aq) ⇄ M⁺²(aq) + 2Z⁻(aq) Kps = S*S² = S³

Thus, the Kps of MZ₂ has a larger value.

b) A saturated solution is a solution that has the maximum amount of salt dissolved, so, the concentration dissolved is solubility. As we can notice from the reactions, the concentration of M⁺² is the same for both salts.

c) The equilibrium will be not modified because the salts have the same solubility. So, let's suppose that the volume of each one is 1 L, so the number of moles of the cation in each one is 4x10⁻⁴ mol. The total number of moles is 8x10⁻⁴ mol, and the concentration is:

8x10⁻⁴ mol/2 L = 4x10⁻⁴ mol/L.

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3 years ago
A gas has a volume of 6.35 L at 88.6 kPa. What will be the volume at standard pressure? Standard Pressure = 101.3 kPa
alukav5142 [94]

Answer:

5.55 L

Explanation:

This excersise can be solved by the Boyle's law.

This law for gases states that the pressure of a gas in a vessel is inversely proportional to the volume of the vessel.

P₁ . V₁  = P₂ . V₂

The law comes from the Ideal Gases Law, in the first term.

P . V = n . R . T  In this case, n . R . T are all constant.

6.35 L . 88.6 kPa = 101.3 kPa . V₂

V₂ = (6.35 L . 88.6 kPa) / 101.3 kPa

V₂ = 5.55 L

It is inversely proportional because, as it happened in this case, pressure was increased, therefore volume decreased.

5 0
3 years ago
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