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vodomira [7]
3 years ago
15

Why is rusted iron an example of an oxidation-reduction reaction

Chemistry
2 answers:
stich3 [128]3 years ago
3 0
Electrons are exchanged.

hope i helped 

can i have branest 
DENIUS [597]3 years ago
3 0

<u>Answer:</u> Because electrons are getting transferred from iron to oxygen.

<u>Explanation:</u>

Oxidation-reduction reaction or redox reaction is defined as the reaction in which oxidation and reduction reaction occur simultaneously.

Oxidation reaction is defined as the reaction in which a substance looses its electrons. The oxidation state of the substance is increasing.

Reduction reaction is defined as the reaction in which a substance gain electrons. The oxidation state of the substance gets reduced.

For the reaction of rusting of iron, the equation follows:

4Fe(s)+3O_2(g)\rightarrow 2Fe_2O_3(s)

<u>On reactant side:</u>

Oxidation state of iron = 0

Oxidation state of Oxygen = 0

<u>On product side:</u>

Oxidation state of iron = +3

Oxidation state of Oxygen = -2

Half reactions of oxidation and reduction are:

Oxidation: Fe(s)\rightarrow Fe^{3+}+3e^-

Reduction: \frac{1}{2}O_2+2e^-\rightarrow O^{2-}

As, oxidation state of iron is increasing from 0 to +3, so it is getting oxidized and undergoes oxidation reaction. And, oxidation state of oxygen is getting decreased from ) to -2, so it is getting reduced and is considered as a reduction reaction.

Here, electrons are getting transferred from iron to oxygen. Hence, rusted of iron is an example of a redox reaction

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Carbon: 75.6g / 12 = 6.29

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C: 6.29 / 0.97 =  6.48 ≈ 6.5

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To get rid of decimals, we multiply by 2  

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The empirical formula = C13H18O2

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