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Hunter-Best [27]

2 years ago

5

Cleo stated that light travels through air in straight paths, and when it moves from air to water, light changes direction, spee

ds up, and bends toward the normal.
Which statement best describes Cleo’s mistake?

Light travels through air and water in angled, scattered paths.
Light does not change direction when it moves from air into water.
Light slows down when it moves from air into water.
Light bends away from the normal when it moves from air into water.

2 answers:

kobusy [5.1K]2 years ago

7 0

Answer:

<em>C</em> is the correct answer on Ed gen uity

Andru [333]2 years ago

4 0

Answer:

Light slows down when it moves from air into water.

Explanation:

It is the property of light that travels faster in a less dense medium.

In a more dense medium, the speed of the light slows down and bends towards the normal.

The air is less dense medium and water is a more dense medium.

When light passes from air to water, the light bends.

This is known as the refraction of light.

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Answer:

$r_{cm}=[12.73,12.73]cm$

Explanation:

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Any differential of mass can be calculated as:

$dm = \lambda*a*d\theta$ Where "a" is the radius of the circle and λ is the linear density of the wire.

The linear density is given by:

$\lambda=M/L=M/(a*\pi/2)=\frac{2M}{a\pi}$

So, the differential of mass is:

$dm = \frac{2M}{a\pi}*a*d\theta$

$dm = \frac{2M}{\pi}*d\theta$

Now we proceed to calculate X and Y coordinates of the center of mass separately:

$X_{cm}=1/M*\int\limits^{\pi/2}_0 {a*cos\theta*2M/\pi} \, d\theta$

$Y_{cm}=1/M*\int\limits^{\pi/2}_0 {a*sin\theta*2M/\pi} \, d\theta$

Solving both integrals, we get:

$X_{cm}=2*a/\pi=12.73cm$

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Therefore, the position of the center of mass is:

$r_{cm}=[12.73,12.73]cm$

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Explanation:

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2 years ago

You hear a sound with a frequency of 256 Hz. The amplitude of the sound increases and decreases periodically: it takes 2 seconds

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To solve this problem it is necessary to take into account the concepts related to frequency and period, and how they are related to each other.

The relationship that defines both agreements is given by the equation,

$f_{beat}=\frac{1}{T}$

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$f_{beat}=\frac{1}{2}$

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<em>Hence option A is incorrect.</em>

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$f_{beat} = 4Hz$

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We can also do this process for 255Hz as $f_1$ and 257 Hz for $f_2$ , then

$f_{beat} =|255Hz-257Hz|$

$f_{beat} = 2Hz$

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$f_{beat} =|255.5Hz-256.5Hz|\\f_{beat} = 1Hz$

<em>Hence option D is incorrect. </em>

We can also do this process for 255.75Hz as $f_1$ and 256.25 Hz for $f_2$ , then

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<em>Hence option E is incorrect. </em>

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