How do I do this a b c

What causes ionic bonding between two atoms?

Marrrta [24]

Answer:

Ionic bonding happens when an atom of an element gives one or more of its electrons to the other element's atom..it usually takes place between metal and non metal atoms...like in NaCl, Na gives its valence electron to chlorine and completes its own octet. Chlorine accepts the electron and completes its own octet too...but now both the atoms have an opposing charge and hence they attract each other to form an IONIC bond.

Ionic bonds are the strongest of the bonds...here complete transfer of electrons takes place unlike covalent bonds.

HOPE IT HELPED..

:)

7 0

1 year ago

Distinguish between a solution in general and an aqueous solution

Sveta_85 [38]

Answer:

What distinguish a solution in general from an aqueous solution is the solvent. A solution in general may contain any solvent, which may be solid, liquid or gas, while an aqueous solution is formed with water as solvent.

Explanation:

A solution in general is a homogeneous mixture in which a substance, named solute, is dissolved, in other substance, name solvent.

Solutions may be in solid, liquid or gas state. There are many kind of solvents. Usually, in a lab you work with liquid solutions. Some liquid solvents are: ethanol, glycerin, hexane, benzene, and water, among many others.

Aqueous solution is a solution where the solvent is water. Of course, the solute may be any one: NaCl, sugar, ethanol, an acid, a base, a salt.

What distinguish a solution in general and an aqueous solution is the solvent.

3 0

2 years ago

In one to two sentences, explain a similarity and difference between the particles in liquid water at 100 c and the particles in

mojhsa [17]

Answer:

The particle theory is used to explain the properties of solids, liquids and gases. The strength of bonds (attractive forces) between particles is different in all three states.

Explanation:

6 0

2 years ago

350.0-mL of 0.50 M hydrogen sulfate solution is reacted with 15.0 grams of sodium hydroxide. What volume of water will be produc

Evgesh-ka [11]

The volume of water that will be produced from the reaction will be 6.3 mL

<h3>Stoichiometric calculation</h3>

From the equation of the reaction:

$H_2SO_4 + 2NaOH --- > Na_2SO_4 + 2H_2O$

The mole ratio of hydrogen sulfate to sodium hydroxide is 1:2.

Mole of hydrogen sulfate = 0.50 x 350/1000 = 0.175 moles

Mole of 15 grams sodium hydroxide = 15/40 = 0.375 moles

Thus, hydrogen sulfide is the limiting reagent.

Mole ratio of hydrogen sulfide to water = 1:2.

Equivalent mole of water = 0.175 x 2 = 0.35 moles

Mass of 0.35 moles of water = 0.35 x 18 = 6.3 grams.

1 gram of water = 1 ml.

Thus, 6.3 grams of water will be equivalent to 6.3 mL

More on stoichiometric calculation can be found here: brainly.com/question/27287858

#SPJ1

6 0

2 years ago

Given the reaction has a percent yield of 86.8 how many grams of aluminum iodide would be required to yield an actual amount of

ioda

Answer:

Approximately $1.29 \times 10^3$ grams.

Explanation:

Let $x$ represent the number of grams of aluminum iodide required to yield that 73.75 grams of aluminum.

In most cases, the charge on each aluminum ion would be +3 while the charge on each iodide ion would be -1. For the charges to balance, there needs to be three iodide ions for every aluminum ion. Hence, the empirical formula for aluminum iodide would be $\rm AlI_3$ .

How many moles of formula units in that $x$ grams of $\rm AlI_3$ ? Start by calculating its formula mass $M(\mathrm{AlI_3})$ . Look up the relative atomic mass of aluminum and iodine on a modern periodic table:

Al: 26.982.
I: 126.904.

$M(\mathrm{AlI_3}) = 1\times 26.982 + 3\times 126.904 = 410.694\; \rm g \cdot mol^{-1}$ .

$n(\mathrm{AlI_3}) = \displaystyle \frac{m}{M} = \frac{x}{410.694}\;\rm mol$ .

Since there's one aluminum ion in every formula unit,

$n(\mathrm{Al}) = n(\mathrm{AlI_3}) = \displaystyle \frac{x}{410.694}\; \rm mol$ .

How many grams of aluminum would that be?

$m(\mathrm{Al}) = n \cdot M = \displaystyle \frac{x}{410.694}\; \times 26.982 = \frac{26.982}{410.694}\, x\; \rm g$ .

However, since according to the question, the percentage yield (of aluminum) is only $86.8\%$ . Hence, the actual yield of aluminum would be:

$\begin{aligned}&\text{Actual Yield} \\ &= \text{Percentage Yield} \times \text{Theoretical Yield} \\ &= 86.8\% \times \frac{26.982}{410.694}\, x \\ &= 0.868 \times \frac{26.982}{410.694}\, x \\ &\approx 0.0570263\, x\; \rm g\end{aligned}$ .

Given that the actual yield is 73.75 grams,

$0.0570263\, x = 73.75$ .

$\displaystyle x = \frac{73.75}{0.0570263} \approx 1.29 \times 10^3\; \rm g$ .

4 0

3 years ago