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IRISSAK [1]
3 years ago
15

Which hydrogen atom would be most easily extracted by a bromine atom?

Chemistry
1 answer:
DerKrebs [107]3 years ago
4 0
The proton which is easily abstracted in 1-Benzyl-3-propylbenzene is the proton which is present on carbon atom in between two phenyl rings, or the central carbon which is shared by two benzene rings.

This easy abstraction of proton is due to its high acidity. Remember those species are always more acidic whose conjugate base is stable. Like the acidity of carboxylic acid is due to stability of the acetate ion. 

In our case the stability of conjugate base arises due to stability of negative ion due to resonance. As shown below, the negative charge can delocalize on both rings.

I have shown the resonance of negative ion on both Phenyl rings with Blue and Pink colors.<span />

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If the standard solutions had unknowingly been made up to be 0.0024 m agno3 and 0.0040 m k2cro4, would this have affected your r
Mnenie [13.5K]
2AgNO3+K2CrO4⇒Ag2CrO4(s)+2KNO3
Hence by mixing 0.0024M AgNO3 and 0.004M
K2CrO4, we will have Ag2CrO4 which is precipitated out and leave us with 
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6 0
3 years ago
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How can a gardener remedy soil that is overly acidic?
DochEvi [55]
A gardener can fix acidic soil by adding lime over time.
4 0
3 years ago
The refining of aluminum from bauxite ore (which contains 50.% Al2O3 by mass) proceeds by the overall reaction 2Al2O3 + 3C → 4Al
iragen [17]

Answer:

18.9 x 10¹³ grams of Bauxite Ore

Explanation:

Al₂O₃ = 50% of Bauxite Ore

Al₂O₃ = 0.5 (Bauxite Ore)--------------------------------------- (1)

Overall reaction:

2Al₂O₃ + 3C → 4Al + 3CO₂--------------------------------------- (2)

[ Al= 27 , O=16, C=12]

From  (2), 2 moles of  Aluminium oxide (Al₂O₃) gives  4 moles of Aluminium

In terms of grams, we can say:

Al₂O₃ = [2(27) +3(16)]

         = 54 +48

         =102grams

2 moles of Al₂O₃ = 2 x102grams

                            =204grams

4 moles of Al = 4 x 27

                      =108 grams

So from (2):

204 grams of  Al₂O₃   = 108 grams of  Aluminium

x grams of  Al₂O₃        =  5.0 x 10¹³grams of Aluminium

Calculating for x:

x =  (204 x  5.0 x 10¹³)/ 108

  = 9.44 x 10¹³ grams

So 9.44 x 10¹³ grams of pure bauxite (Bauxite) is required.

However the to calculate the quantity of raw bauxite, we use (1):

Bauxite ore = Pure Bauxite/0.5

                   =   9.44 x 10¹³ grams/0.5

                   =   18.88 x 10¹³ grams

                    ≈ 18.9 x 10¹³ grams

 

8 0
3 years ago
Calculate the ratio of H+ ions to OH– ions at a pH = 8. Find the concentration of H+ ions to OH– ions listed in Table B of your
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Answer:

0.00000001 mol/L

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