Answer:
7 gram of Na2SO4 should be required to prepare 0.5L of a 0.100 M solution.
Explanation:
First of all the molecular weight of Na2SO4 is 142.08 gram.Now we all know that if the molecular weight of a compound is dissolved in 1000ml or 1 litee of water then the strength of that solution becomes 1 M.
According to the given question we have to prepare 0.100 M solution
1000 ml of solution contain 142.08×0.1= 14.208 gram Na2SO4
1 ml of solution contain 14.208÷1000= 0.014 gram
0.5L or 500ml of solution contain 0.014×500= 7gram Na2SO4.
So it can be stated that 7 gram of Na2SO4 should be required to prepare 0.5L of a 0.100M solution.
Density = mass / volume
= 69g / 23 ml
= 3 g / ml.
Thus, the density of the sample is 3 grams per ml or 3g/ ml
The total charge on an atom comes from protons and electrons.
The proton is positively charged while the electron is negatively charged. A neutral atom would have an equal number of protons and electrons.
An atom with more protons than electrons will be positively charged while those with more electrons than protons will be negatively charged.
More on the atom can be found here: brainly.com/question/1641336
an element's name, chemical symbol, atomic number, atomic mass.
IDK what you are even asking for
