Answer:
A) Alkaline Earth Metals
Explanation:
Area Marked A would be Alkali Metals
Area Marked B would be Alkaline Earth Metals
Area Marked C would be Transition Metals
Area marked H would be Halogens
According to this formula:
㏑(K2/K1) = Ea/R(1/T1 - 1/T2)
when K is the rate constant
Ea is the activation energy
R is the universal gas constant
and T is the temperature K
when K is doubled so K2: K1 = 2:1 & R = 8.314 J.K^-1.mol^-1
and T1 = 10 +273 = 283 k & T2 = 21 + 273 = 294 k
So by substitution:
㏑2 =( Ea / 8.314) (1/283 - 1/294 )
∴ Ea = 43588.9 J/mol = 43.6 KJ/mol
Answer:
First, it is easiest if you write the compete molecular equation:
AgNO3(aq) + KCl(aq) ==> AgCl(s) + KNO3(aq) .. molecular equation.
You must also know or look up which compounds are soluble (aq) and which are not (s). In this case, silver chloride (AgCl) is not soluble. Thus, the net ionic equation is...
Ag+(aq) + Cl-(aq) ==> AgCl(s)
Answer:
2.409 x 10²⁴
Explanation:
There are two nitrogens for every mole of NH₄NO₃
Since there are two moles, that means there are 4 nitrogens
There are 6.022 x 10²³ atoms in every mole of any element
(6.022 x 10²³) x 4 = 2.4088 x 10²⁴
Use sig figs to round it to 2.409 x 10²⁴
Answer:
Is better use the Benedict's test by the increase in the amount of the products if the enzyme is a reductase
Explanation:
The Benedict's test works by the reaction of the reducing sugars with the ion cupric of the reactive. If the enzyme is a reductase (degrades polysaccharides into bi o monosaccharides), it should cut the polysaccharide bond and the products would react with the Benedict's cupric ion
I hope you undestand me
