Answer:
Explanation:
Given parameters:
Concentration of H₃O⁺ = 5.6 x 10⁻²M
Solution:
To solve for the concentration of H₃O⁺ in the solution, we simply use the expression below:
pH = -log₁₀[H₃O⁺]
where [H₃O⁺] = 5.6 x 10⁻²M is the concentration of H₃O⁺
pH = -log₁₀[5.6 x 10⁻²] = - x -1.25 = 1.25
Answer:
The percentage of Lake Parsons which has evaporated since it became isolated is 68.24%.
Explanation:
The concentration of salt dissolved in Lake Parson = 21.0 g/L
= In 1 L of lake Parson water = 21.0 g of salt
The concentration of salt in several nearby non-isolated lakes = 6.67 g/L
The salt concentration in Lake Parsons before it became isolated = 6.67 g/L
In 1 L of lake water = 6.67 g of salt
If 1 L of lake Parson water has 6.67 g of salt. Then 21.0 grams of salt will be in ;

Water evaporated = 3.15 L - 1 L = 2.15 L
The percentage of Lake Parsons which has evaporated since it became isolated:

For every 1 mole of C6H12O6, you need 6 moles of water. Multiply the 2.5 moles you are trying to make by the 6 of water you need, and 4) 15 is your answer.
Methane is CH4
Ethane is. C2H6
Method by ☆cracking alkanes☆
In this case, by cracking methane
Cracking alkanes is the method used to split a long alkane structure into smaller alkanes using high temperature and a catalyst.
e.g. C2H6 -> CH4 + CH2
A cubic meter is about the same as the volume occupied by a _____.
Answer: Washing machine
Hoped this helped... :)
;3;