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topjm [15]
3 years ago
7

A bucket of water with total mass 23 kg is attached to a rope, which in turn is wound around a 0.050-m radius cylinder at the to

p of a well. the bucket is raised to the top of the well and released. the bucket is moving with a speed of 8.0 m/s upon hitting the water surface in the well. what is the angular speed of the cylinder at this instant?
Physics
1 answer:
Elodia [21]3 years ago
7 0

As we know the relation between linear speed and angular speed as

v = R\omega

we will say

v = 8 m/s

R = 0.05 m

so here we can say that angular speed will be given as

\omega = \frac{8}{0.05}

\omega = 160 rad/s

so it is rotating at angular speed 160 rad/s

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While rowing in a race, John does 132 J of work while pulling the oar 0.800 m.
HACTEHA [7]

Answer:

i got u!!! john's arms exert a force of 165 newtons.

6 0
2 years ago
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A conducting sphere of radius r1 = 0.21 m has a total charge of Q = 2.9 μC. A second uncharged conducting sphere of radius r2 =
wolverine [178]

Answer:

what is the anser

Explanation:

4 0
3 years ago
Any projectile always has a constant vertical acceleration of _______.
Mashcka [7]

Answer:

The answer to your question is: C. -9.81 m/s²

Explanation:

A. 9.81 m/s²  acceleration is considered positive when it goes to the center of the earth, so this option is incorrect.

B. 0 m/s²  This option is incorrect because acceleration is 0 for a linear motion without acceleration.

C. -9.81 m/s²  If a projectile goes to the sky, then the acceleration will be negative.

D. It is not constant. Acceleration is constant.

8 0
3 years ago
What is the magnitude of the torque about his shoulder if he holds his arm straight out to his side, parallel to the floor
const2013 [10]

Complete Question

An athlete at the gym holds a 3.0 kg steel ball in his hand. His arm is 70 cm long and has a mass of 4.0 kg. Assume, a bit unrealistically, that the athlete's arm is uniform.

What is the magnitude of the torque about his shoulder if he holds his arm straight out to his side, parallel to the floor? Include the torque due to the steel ball, as well as the torque due to the arm's weight.

Answer:

The torque is  \tau = 34.3 \  N\cdot m

Explanation:

From the question we are told that

   The mass of the steel ball is  m  =  3.0 \  kg

    The length of arm is  l =  70 \ cm  = 0.7 \  m

    The mass of the arm is m_a  = 4.0 \  kg

Given that the arm of the athlete is uniform them the distance from the shoulder to the center of gravity of the arm is mathematically represented as

       r = \frac{l}{2}

=>    r = \frac{ 0.7}{2}  

=>    r = 0.35 \ m  

Generally the magnitude of torque about the athlete shoulder is mathematically represented as

      \tau =  m_a * g * r  + m * g *  L

=>    \tau =  4 * 9.8 * 0.35 + 3 * 9.8 *  0.70

=>    \tau = 34.3 \  N\cdot m

5 0
2 years ago
A force of 85 N is used to push a box along the floor a distance of 15 m. How much work was done?
denpristay [2]

Answer:

1275J

Explanation:

Given parameters:

Force on box  = 85N

Distance moved  = 15m

Unknown:

Work done  = ?

Solution:

Work done is the amount of force applied on a body to move it through a specific distance.

 Work done  = Force x distance

Now insert the parameters and solve;

 Work done = 85 x 15  = 1275J

4 0
3 years ago
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