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lozanna [386]
4 years ago
10

How does the currently accepted model of the nucleus provide evidence of the existence of the strong nuclear force?

Physics
1 answer:
olganol [36]4 years ago
4 0

Answer:

Protons and neutrons are all attracted to each other as a result - the strong nuclear force. This is an attractive force that only has an effect over a very short range in the nucleus.

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Find the magnitude of the impulse delivered to a soccer ball when a player kicks it with a force of 1450 N . Assume that the pla
juin [17]

To solve this problem we will apply the concept of Impulse. Which is described as the product between the Force and the change in time. Mathematically this can be described as

I = F \Delta t

Where,

F = Force

\Delta t= Time

Our values are given as,

F = 1450N

\Delta t = 5.1*10^{-3} s

Replacing we have,

I = (1450)(5.1*10^{-3})

I = 7.395Kg\cdot m/s

Therefore the impulse delivered to the soccer ball is 7.395Kg\cdot m/s or  7.395N\cdot s

4 0
3 years ago
Objects with less density than water will?
ruslelena [56]

Objects with less density than water will float when you put them in water.

Objects with greater density than water will sink when you put them in water.

6 0
3 years ago
B. Study the given figure and calculate the area of the leaf
yanalaym [24]

Answer:

19 cm sq

Explanation:

you have to count one full and half area occupied by leaf in each box, then you have to multiply with 1 cm sq.

4 0
3 years ago
What is the difference between a steep and shallow slope
Airida [17]
Whether a line is "steep" or "shallow" depends on the slope of the line. In the equation y=mx+b, m is the slope. In your first equation, 1/2x+4, the slope would be 1/2 which means there is 1 increase in the vertical, or y, value for each 2 increases in the horizontal, or x value. This line would be shallow.
4 0
4 years ago
Read 2 more answers
The temperature coefficient of a certain conducting material is 5.74 × 10-3 (°C)-1. (a) At what temperature would the resistance
Alex777 [14]

Answer:

Temperature at which the resistance is twice the resistance at 20^{\circ}C is 194.216^{\circ}C

Solution:

As per the question:

Temperature coefficient, \alpha = 5.74\times 10^{- 3}^{\circ}C

Reference temperature, T_{o} = 20^{\circ}C

Resistance, R_{t} = 2R_{o}

Now, using the formula:

R_{t} = R_{o}(1 + \alpha \Delta T)

2R_{o} = R_{o}(1 + \alpha \times (T _ T_{o}))

2 = 1 + 5.74\times 10^{- 3}\times (T - 20^{\circ})

\frac{1}{5.74\times 10^{- 3}} = T - 20^{\circ}

T = 174.216 + 20 = 194.216^{\circ}

  • Yes, this temperature holds for all all the conductors of copper, irrespective of the size and shape of the conductor.

5 0
3 years ago
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