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3 years ago

A gas occupies 900.0 ML at temperatures of 27.0 Celsius. What is the volume at 123.0 celsius

Chemistry

2 answers:

Artemon [7]3 years ago

4 0

Answer:

1188.0 mL.

Explanation:

We can use the general law of ideal gas: PV = nRT.

where, P is the pressure of the gas in atm.

V is the volume of the gas in L.

n is the no. of moles of the gas in mol.

R is the general gas constant,

T is the temperature of the gas in K.

If n and P are constant, and have two different values of V and T:

V₁T₂ = V₂T₁

V₁ = 900 mL, T₁ = 27.0°C + 273 = 300.0 K.

V₂ = ??? mL, T₂ = 123.0°C + 273 = 396.0 K.

∴ V₂ = V₁T₂/T₁ = (900 mL)(396 K)/(300.0 K) = 1188.0 mL.

Tamiku [17]3 years ago

3 0

Answer:

1188 ml

Explanation:

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The given data is as follows.

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1 atoms weight = $\frac{38}{6.023 \times 10^{26}}$

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Therefore, total weight of atoms in a unit cell will be as follows.

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Now, we will calculate the volume of a lattice with lattice constant 'a' (cubic diamond) as follows.

= $a^{3}$

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Formula to calculate density of diamond cell is as follows.

Density = $\frac{mass}{volume}$

= $\frac{37.06 \times 10^{-26}}{0.127 \times 10^{-27} m^{3}}$

= 2918.1 $g/m^{3}$

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Answer:

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Explanation:

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