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zepelin [54]
3 years ago
5

How to find the volume of this shape? I’m really struggling!!!!

Mathematics
2 answers:
Damm [24]3 years ago
8 0

I am pretty sure this is how you do it! Hope this helps!

lina2011 [118]3 years ago
7 0

Answer:

6840 yd ³

Step-by-step explanation:

In this case you could find the area of a trapezoid then multiply that by the high of the whole thing.

a = (25+32)(12)/2

a = (57)(12)/2

a = (684)/2

a = 342

Now multiply by the height of the figure

v = 342 × 20

6840 yd ³

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You throw a ball up and its height h can be tracked using the equation h=2x^2-12x+20.
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1) There is no maximum height

2) The ball will never land

Step-by-step explanation:

<u>Derivatives</u>

Sometimes we need to find the maximum or minimum value of a function in a given interval. The derivative is a very handy tool for this task. We only have to compute the first derivative f' and have it equal to 0. That will give us the critical points.

Then, compute the second derivative f'' and evaluate the critical points in there. The criteria establish that

If f''(a) is positive, then x=a is a minimum

If f''(a) is negative, then x=a is a maximum

1)

The function provided in the question is

h(x)=2x^2-12x+20

Let's find the first derivative

h'(x)=4x-12

solving h'=0:

4x-12=0

x=3

Computing h''

h''(x)=4

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2)

To find when will the ball land, we set h=0

2x^2-12x+20=0

Simplifying by 2

x^2-6x+10=0

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x^2-6x+9+10-9=0

Factoring and rearranging

(x-3)^2=-1

There is no real value of x to solve the above equation, so the ball will never land.

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3 years ago
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