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3 years ago

What are the derivatives of alkanoic acid?

Chemistry

1 answer:

Nuetrik [128]3 years ago

4 0

The answer to your question is,

Carboxylic acids themselves, carboxylates (deprotonated carboxylic acids), amides, esters, thioesters, and acyl phosphates.

-Mabel <3

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Which of the following statements is true?

AlekseyPX

Answer:

Explanation:

Its eurasian plate.

8 0

3 years ago

he mineral rhodochrosite [manganese(II) carbonate, MnCO3] is a commercially important source of manganese. Write a half-reaction

valina [46]

Answer:

$MnCO_{3}+2H_{2}O-2e^{-}\rightarrow MnO_{2}+HCO_{3}^{-}+3H^{+}$

Explanation:

Half reaction: $MnCO_{3}\rightarrow MnO_{2}$

(1) $CO_{3}$ balance: $MnCO_{3}\rightarrow MnO_{2}+HCO_{3}^{-}$

(2)H and O balance in acidic medium: $MnCO_{3}+2H_{2}O\rightarrow MnO_{2}+HCO_{3}^{-}+3H^{+}$

(3) charge balance: $MnCO_{3}+2H_{2}O-2e^{-}\rightarrow MnO_{2}+HCO_{3}^{-}+3H^{+}$

Hence balanced half-reaction: $MnCO_{3}+2H_{2}O-2e^{-}\rightarrow MnO_{2}+HCO_{3}^{-}+3H^{+}$

7 0

3 years ago

Read 2 more answers

You have 363 mL of a 1.25M potassium chloride solution, but you need to make a 0.50M potassium chloride solution. How many milli

maxonik [38]

Answer:- 544.5 mL of water need to be added.

Solution:- It is a dilution problem. The equation used for solving this type of problems is:

$M_1V_1=M_2V_2$

where, $M_1$ is initial molarity and $M_2$ is the molarity after dilution. Similarly, $V_1$ is the volume before dilution and $V_2$ is the volume after dilution.

Let's plug in the values in the equation:

$1.25M(363mL)=0.50M(V_2)$

$V_2=\frac{1.25M(363mL)}{0.50M}$

$V_2=907.5mL$

Volume of water added = 907.5mL - 363mL = 544.5 mL

So, 544.5 mL of water are need to be added to the original solution for dilution.

3 0

3 years ago

In the equation, 2Al (s) + 3Cl2 (g) → 2AlCl3 (s), the large number “3” in front of the Cl2 indicates:

dybincka [34]

In the equation,

2Al(s) + 3Cl2(g) —> 2AlCl3(s),

the large number "3" in front of Cl2 indicates the the number of moles of Chlorine molecules needed to balance the equation.

Hope this will help you.

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5 0

3 years ago

Read 2 more answers

San Alfonso Del Mar, a resort in Chile, has the world's largest swimming pool.

AlexFokin [52]

Answer:

2,500,000 litres or 2.5 megalitres of water.

Olympic size pools measure: 50 metres long, 25 metres wide, and a minimum of 2

metres deep.

(25m x 50m x 2m = 2,500m3; 1L = 0.001m3 so 2,500 x 1000 = 2,500,000L)

660,430 gallons of water.

50 meters = 164.041995 feet (a)

25 meters = 82.0209975 feet (b)

2 meters = 6.5616798 feet (c)

Volume = (a) * (b) * (c) = 88,286.66721 cubic feet Explanation:

8 0

3 years ago