Ionization energy increases from left to right because the left wants to lose elctrons and the right wants to gain electron
As you go a group it is easier lose lose because the electrons are farther away from the nucleus and there is less attraction from the positive charges.
It should be 3p3. the p level can hold 6 electrons
Rubidium group 1, 1 valence electrons very reactive
Mg2,2 very reactive
Al 3, 3 reactive
Answer : Option C) The kinetic energy decreases as potential energy increases.
Explanation : As the target is fired high on the wall, the change in the energy that is observed as the arrow moves towards the target is kinetic energy starts to decrease as the arrow reaches nearer towards the target and the potential energy is observed to increase. So, in short the energy transformation is from kinetic energy from a moving arrow to potential energy when the arrow hits the target.
Answer:
Glycogen: It is made up of a large chain of molecules. ...
Cellulose: The cell wall of the plants is made up of cellulose. ...
Starch: It is formed by the condensation of amylose and amylopectin. ...
Insulin: It is made up of a number of fructofuranose molecules linked together in chains.
Explanation:
Yes, it is easier to remove a core or a valence electron from an atom.
Valence electrons are the furthest from the positive charge (protons) and therefore also appear to be easier to remove than core electrons this signifies that electrons need less energy to transfer out from the atom. Electrons orbit around a nucleus in orbitals.
Quantum mechanics determines these orbitals and the energy required to remove each electron from the atom. Each of these orbitals helps to form an electron shell in the atom. Valence electrons are electrons in an atom's outermost atomic shell that circle the nucleus.
Closer to the nucleus, electrons are in filled orbitals and are referred to as core electrons. This distinction is due to the fact that electric force is an inverse square law. Furthermore, inner shell core electrons have lower energy levels than outer shell valence electrons. This means that electrons in the inner shells can absorb energy and migrate (jump) to the outer shells.
Learn more about Valance electrons here:
brainly.com/question/27569184
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<u>Answer:</u> The predicted cell potential of the cell is +0.0587 V
<u>Explanation:</u>
The half reactions for the cell is:
<u>Oxidation half reaction (anode):</u> 
<u>Reduction half reaction (cathode):</u> 
In this case, the cathode and anode both are same. So, 
will be equal to zero.
To calculate cell potential of the cell, we use the equation given by Nernst, which is:
![E_{cell}=E^o_{cell}-\frac{0.0592}{n}\log \frac{[M^{2+}_{(diluted)}]}{[M^{2+}_{(concentrated)}]}](https://tex.z-dn.net/?f=E_%7Bcell%7D%3DE%5Eo_%7Bcell%7D-%5Cfrac%7B0.0592%7D%7Bn%7D%5Clog%20%5Cfrac%7B%5BM%5E%7B2%2B%7D_%7B%28diluted%29%7D%5D%7D%7B%5BM%5E%7B2%2B%7D_%7B%28concentrated%29%7D%5D%7D)
where,
n = number of electrons in oxidation-reduction reaction = 2
= ?
![[M^{2+}_{(diluted)}]](https://tex.z-dn.net/?f=%5BM%5E%7B2%2B%7D_%7B%28diluted%29%7D%5D)
= 0.05 M
![[Zn^{2+}_{(concentrated)}]](https://tex.z-dn.net/?f=%5BZn%5E%7B2%2B%7D_%7B%28concentrated%29%7D%5D)
= 4.808 M
Putting values in above equation, we get:
Hence, the predicted cell potential of the cell is +0.0587 V
