4 years ago

What force is required to accelerate a body with the mass of 15 kilograms at a rate of 8m/s2?

Physics

1 answer:

Tom [10]4 years ago

8 0

Force = mass * acceleration
F = 15 *8 = 120 Newton

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What force is needed to accelerate a 0.5kg football at a rate of 40m/s

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Force=mass x acceleration
f= 0.5 x40
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4 years ago

A small balloon is released at a point 150 feet away from an observer, who is on level ground. If the balloon goes straight up a

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Answer:

$\dfrac{dz}{dt}=0.65\ ft/s$

Explanation:

Given that

x= 150 ft

$\dfrac{dy}{dt}= 7\ ft/s$

y= 14 ft

From the diagram

$z^2=x^2+y^2$

When ,x= 150 ft and y= 14 ft

$z^2=150^2+14^2$

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z=150.74 ft

$z^2=x^2+y^2$

By differentiating with respect to time t

$2z\dfrac{dz}{dt}= 2x\dfrac{dx}{dt}+2y\dfrac{dy}{dt}$

$z\dfrac{dz}{dt}= x\dfrac{dx}{dt}+y\dfrac{dy}{dt}$

Here x is constant that is why

$\dfrac{dx}{dt}=0$

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Now by putting the values in the above equation we get

$150.74\times \dfrac{dz}{dt}=14\times 7$

$\dfrac{dz}{dt}=\dfrac{14\times 7}{150.74}\ ft/s$

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Therefore the distance between balloon and observer increasing with 0.65 ft/s.

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A small flashlight bulb provides a resistance of 3 Ω to the 300 mA current that runs through it. Determine the voltage of the ba

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V=IR

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A 3.7-kg object is acted on by two forces. One of the forces is 11 N acting toward the

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Answer:

F₂ = -7.3 N

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Given that,

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First force, F₁ = 11 N

The net acceleration of the object is 1 m/s².

We know that,

F₁+F₂ = ma

11+F₂ = (3.7)(1)

F₂ = 3.7-11

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so, the other force is 7.3 N and it is acting in west direction.

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Answer:

Chess

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Chess is considered a sport

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