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Alja [10]
3 years ago
8

When a baseball player swings a bat slowly as part of their warm up, that is an example of ____________________________ stretchi

ng.
Physics
1 answer:
Artist 52 [7]3 years ago
3 0

Static

<u>Explanation:</u>

The term warm-up in sport is defined as a period of preparatory  exercise to enhance subsequent competition or training performance . A pre-game warm-up for team sports typically  includes a period of sub maximal running, static stretching of the major  muscle groups and sport specific movements incorporating various  range of motion (ROM) exercises with skill-based drills executed at, or  just below game intensity

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Gravity. It is the pull we feel. Neither motion could happen nor mass could keep us on the ground without the existence of gravity.

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What is the mass in kg of a leopard in a tree if the tree branch is 36 m up and the leopard's gravitational potential energy is
ElenaW [278]

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83.3kg

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5 0
3 years ago
17 points
const2013 [10]

The velocity of the cannonball is 150 m/s,  the right option is B. 150 m/s.

The question can be solved, using Newton's second law of motion.

Note: Momentum of the cannon = momentum of the cannonball.

<h3>Formula:</h3>
  • MV = mv................. Equation 1

<h3>Where:</h3>
  • M = mass of the cannon
  • m = mass of the cannonball
  • V = velocity of the cannon
  • v = velocity of the cannonball

Make v the subject of the equation.

  • v = MV/m................ Equation 2

From the question,

<h3>Given: </h3>
  • M = 500 kg
  • V = 3 m/s
  • m = 10 kg.

Substitute these values into equation 2.

  • v = (500×3)/10
  • v = 150 m/s.

 

Hence, The velocity of the cannonball is 150 m/s,  the right option is B. 150 m/s.

Learn more about Newton's second law here: brainly.com/question/25545050

3 0
2 years ago
A solenoid with 3,000.0 turns is 70.0 cm long. If its self-inductance is 25.0 mH, what is its radius? (The value of μ0 is 4π x 1
nevsk [136]

Answer:

A. 2.2*10^-2m

Explanation:

Using

Area = length x L/ uo xN²

So A = 0.7m * 25 x 10^-3H /( 4π x10^-7*

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A = 17.5*10^-3/ 1.13*10^-5

= 15.5*10^-2m²

Area= π r ²

15.5E-2/3.142 = r²

2.2*10^2m

Explanation:

5 0
3 years ago
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