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Alja [10]
3 years ago
8

When a baseball player swings a bat slowly as part of their warm up, that is an example of ____________________________ stretchi

ng.
Physics
1 answer:
Artist 52 [7]3 years ago
3 0

Static

<u>Explanation:</u>

The term warm-up in sport is defined as a period of preparatory  exercise to enhance subsequent competition or training performance . A pre-game warm-up for team sports typically  includes a period of sub maximal running, static stretching of the major  muscle groups and sport specific movements incorporating various  range of motion (ROM) exercises with skill-based drills executed at, or  just below game intensity

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The initial kinetic energy imparted to a 0.25 kg bullet is 1066 J. The acceleration of gravity is 9.81 m/s 2 . Neglecting air re
lubasha [3.4K]

Answer:

The range of the bullet is 0.435 kilometers.

Explanation:

According to the problem, maximum height is equal to the range of the bullet. That is:

\Delta x = \Delta y

Where:

\Delta x - Range of the bullet, measured in meters.

\Delta y - Maximum height of the bullet, measured in meters.

By the Principle of Energy Conservation, gravitational potential energy reaches its maximum at the expense of the initial kinetic energy. That is to say:

K_{1} = U_{2}

Where:

K_{1} - Kinetic energy at point 1, measured in joules.

U_{1} - Gravitational potential energy at point 2, measured in joules, and:

U_{2} = m\cdot g \cdot \Delta y

Where:

m - Mass of the bullet, measured in kilograms.

g - Gravitational constant, measured in meters per square second.

The maximum height is now cleared:

K_{1} = m\cdot g \cdot \Delta y

\Delta y = \frac{K_{1}}{m\cdot g}

If K_{1} = 1066\,J, m = 0.25\,kg and g = 9.81\,\frac{m}{s^{2}}, the maximum height is now computed:

\Delta y = \frac{1066\,J}{(0.25\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)}

\Delta y = 434.791\,m

\Delta y = 0.435\,km

Lastly, the range of the bullet is 0.435 kilometers.

3 0
3 years ago
Which of the following could be classified as a problem that could be answered with a technological design?
loris [4]
I think the answer is 4) All of the above!! :)
4 0
4 years ago
Sheila eats an energy bar right before she goes on a run. What energy changes will occur in sheila as she runs after eating?
LiRa [457]
The energy bar eaten by Sheila has chemical energy locked up inside it. This chemical energy is converted to mechanical energy in form of potential and kinetic energy and this in turn is converted to heat energy as the run progresses. Thus, the energy changes are: chemical energy to mechanical energy [kinetic and potential] and finally to heat energy.
8 0
3 years ago
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A 20-newton weight is attached to a spring.
Makovka662 [10]

Answer:

40 N/m

Explanation:

The diagram attached is used to answer the question

We know from Hooke's law that extension is directly proportional to the applied force hence

F=kx where x is extension, F is applied force and k is the spring constant. Making k the subject of the formula then

k=\frac {F}{k}

From the attached diagram extension is given by subtracting unstretched spring from stretched spring hence extension, x=1-0.5=0.5m

Substituting 20 N for F and 0.5 m for x then

k=\frac {20}{0.5}=40 N/m

8 0
3 years ago
What are the two naturally occurring liquid elements?​
insens350 [35]

Answer:

Explanation:

The two liquid elements are bromine and mercury. Many elements naturally occur as gases: hydrogen, nitrogen, oxygen, fluorine, chlorine, and all the noble gases (Group VIIIA elements). The remaining elements exist as solids.

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3 years ago
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