The answer is b i just did the test
Answer:
The initial velocity of the ball is <u>39.2 m/s in the upward direction.</u>
Explanation:
Given:
Upward direction is positive. So, downward direction is negative.
Tota time the ball remains in air (t) = 8.0 s
Net displacement of the ball (S) = Final position - Initial position = 0 m
Acceleration of the ball is due to gravity. So, 
(Acting down)
Now, let the initial velocity be 'u' m/s.
From Newton's equation of motion, we have:
Plug in the given values and solve for 'u'. This gives,
Therefore, the initial velocity of the ball is 39.2 m/s in the upward direction.
Explanation:
G is the universal constant of gravitation, approximately 6.67×10⁻¹¹ m³/kg/s².
g is the acceleration due to gravity. It's defined by the universal law of gravity as:
g = MG / r²
where M is the mass of the planet and r is the distance from the planet's center to the object.
Near the surface of the Earth, g is approximately 9.8 m/s².
With angular momentum quantum number l = 2. in units of ħ, the value of l will be 2.4494 h.
<h3>What is the angular momentum quantum number?</h3>
The total angular momentum quantum number in quantum mechanics parametrizes the total angular momentum of a particular particle by combining its orbital angular momentum and intrinsic angular momentum.
Given the angular momentum quantum number l = 2. in units of ħ. Therefore, the value of L can be written as,
L = √[l (l + 1)]
L = √[2 (2 + 1)]
L = √[2 (3)]
L = √6
L = 2.4494 h
Hence, With angular momentum quantum number l = 2. in units of ħ, the value of l will be 2.4494 h.
Learn more about Angular momentum quantum numbers here:
brainly.com/question/16725426
#SPJ4
Answer:
is the firts one because i due it in jannuary i will know all answer
Explanation:
