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Aneli [31]
3 years ago
13

Pls help i have test

Physics
2 answers:
Ne4ueva [31]3 years ago
7 0
I think no is the correct ans for the question ✅
ludmilkaskok [199]3 years ago
5 0

Answer:

I think the answer is a no. I guess

Explanation:

don't mind if it is write or wrong

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FORCE AND DISPLACEMENT AT AN ANGLE A sailor pulls a boat a distance of 30.0 m along a dock using a rope that makes a 25.0° angle
Bingel [31]

Answer: 6117.58 J

Explanation:

We know that W=Fd*cos(theta) where theta is the angle between the displacement and the force.

In this case, we are given that F=225 N, d=30 m, and theta=25 degrees.

Plugging all this in we get

W=225*30*cos(25)=6117.58 J

7 0
3 years ago
A particle has 3 x 10^15 eV has a charge of 3uC is placed on a certain field.
Vinvika [58]

Answer:

no se porque xD jajjakajajjajajajjaj

8 0
2 years ago
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Olivia wants to find out whether a substance will fluoresce. She says she should put it in a microwave oven. Do you agree with h
Sophie [7]
I disagree.
Many substances show fluorescence under ULTRAVIOLET light, NOT microwaves. :)
5 0
3 years ago
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A photon ionizes a hydrogen atom from the ground state. The liberated electron 11. recombines with a proton into the first excit
anygoal [31]

Answer:

a) 23.2 e V

b) energy of the original photon is 36.8 eV

Explanation:

given,

energy at ground level = -13.6 e V

energy at first exited state = - 3.4 e V

A photon of energy ionized from ground state and electron of energy K is released.

h ν₁ - 13.6 = K

K combine with photon in first exited state giving out photon of energy

h\nu_2 =\dfrac{hc}{\lambda}=\dfrac{12400}{466}

            = 26.6 e V

h c = 6.626 ×  10⁻³⁴ ×  3  × 10⁸  = 12400 e V A°

K + ( 3.4 ) = 26.6 e V

a) energy of free electron

K = 26.6 - 3.4 = 23.2 e V

b) energy of the original photon

h ν₁ - 13.6 = K

h ν₁  = 23.2 + 13.6

       = 36.8 e V

energy of the original photon is 36.8 eV

3 0
3 years ago
3. What is a manometer used to determine?​
Gemiola [76]

Answer:

It's used to indicate pressure

3 0
2 years ago
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