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Gnesinka [82]
3 years ago
9

2.1 The reaction of nitrogendioxide and carbonmonoxide in the gas state to form carbondioxide and nitricoxide is represented by

the equation on the figure: What are solutions of questions on the figure?

Chemistry
1 answer:
neonofarm [45]3 years ago
5 0

Answer:

The reaction between nitrogen dioxide and carbon monoxide is

NO2(g)+CO(g)→NO(g)+CO2(g)

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Please help asappp‍♀️!
solniwko [45]
Can you show me the passage?
6 0
3 years ago
Read 2 more answers
Automobile airbags contain solid sodium azide, NaN3, that reacts to produce nitrogen gas when heated, thus inflating the bag. 2N
Vitek1552 [10]

Answer : The value of work done for the system is 1144.69 J

Explanation :

First we have to calculate the moles of NaN_3

\text{Moles of }NaN_3=\frac{\text{Mass of }NaN_3}{\text{Molar mass of }NaN_3}

Molar mass of NaN_3 = 65.01 g/mole

\text{Moles of }NaN_3=\frac{20.2g}{65.01g/mole}=0.311mole

Now we have to calculate the moles of nitrogen gas.

The balanced chemical reaction is,

2NaN_3(s)\rightarrow 2Na(s)+3N_2(g)

From the balanced reaction we conclude that

As, 2 mole of NaN_3 react to give 3 mole of N_2

So, 0.311 moles of NaN_3 react to give \frac{0.311}{2}\times 3=0.466 moles of N_2

Now we have to calculate the volume of nitrogen gas.

Using ideal gas equation:

PV=nRT

where,

P = Pressure of N_2 gas = 1.00 atm

V = Volume of N_2 gas = ?

n = number of moles N_2 = 0.466 mole

R = Gas constant = 0.0821L.atm/mol.K

T = Temperature of N_2 gas = 22^oC=273+22=295K

Putting values in above equation, we get:

1.00atm\times V=0.466mole\times (0.0821L.atm/mol.K)\times 295K

V=11.3L

As initially no nitrogen was present. So,

Volume expanded = Volume of nitrogen evolved

Thus,

Expansion work = Pressure × Volume

Expansion work = 1.00 atm × 11.3 L

Expansion work = 11.3 L.atm

Conversion used : (1 L.atm = 101.3 J)

Expansion work = 11.3 × 101.3 = 1144.69 J

Therefore, the value of work done for the system is 1144.69 J

5 0
3 years ago
6) Which of these elements is a metal?<br> E) C<br> D) N<br> A) O<br> C) Ne<br> B) Ca
sertanlavr [38]

Answer:

Ca

Explanation:

It is on the left side of the periodic table where metals are located.

4 0
3 years ago
Read 2 more answers
How many grams of ammonia gas can be formed from 54.1 g of hydrogen gas
Murrr4er [49]

Answer:

304.19 g

Explanation:

M(H2) = 2*1 = 2 g/mol

54.1 g H2 * 1 mol H2/2gH2 = 27.05 mol H2        

                                   3H2 + N2 ------> 2NH3

from reaction             3 mol                  2 mol

given                   27.05 mol                 x mol

x = 27.05*2/3 = 18.03 mol NH3

M(NH3) = 14 +3*1 = 17 g/mol

18.03 mol NH3 * 17 g NH3/ 1 mol NH3 ≈ 307 g

Closeet answer is 304.19 g.

4 0
4 years ago
A solution that dissloves completely is called a?
snow_tiger [21]

soluble substances dissolves in solvents

3 0
3 years ago
Read 2 more answers
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