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Vsevolod [243]
3 years ago
15

2, 3, 6, 8, . . . is an example of an infinite alternating series. True False

Mathematics
2 answers:
vaieri [72.5K]3 years ago
8 0
Answer: False.

Explanation: An alternating series is on in which the alternate terms are negative & positive.
Example, <span>1/2 − 1/4 + 1/8 − 1/16 + ⋯  is an alternating series.

but here, in the given series - all numbers are positive . Hence, it is not an infinite alternating series.

</span>
zysi [14]3 years ago
6 0

Answer:

false

Step-by-step explanation:

took the test

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Luigi is an urban planner. As an independent contractor, he charges $140 fee plus $25 per hour for each contract with the city.
Bess [88]

Answer:

D. Y = 25x + 140

Step-by-step explanation:

4 0
2 years ago
The symbol ⊕ is used to denote exclusive or, so p ⊕ q ≡ (p v q) ^ ~ (p ^ q).
Elan Coil [88]

I'll use text forms of the logical symbols because copying/pasting on mobile is annoying.

⊕ = XOR

∨ = OR

∧ = AND

~ = NOT

↔ = IFF (meaning "if and only if")

→ = IMP (short for "implies")

and for logical equivalence I'll use a regular equal sign.

Then

p XOR q = (p OR q) AND NOT (p AND q)

(a) By definition of XOR, we have

p XOR p = (p OR p) AND NOT (p AND p)

= p AND NOT p

and this is tautologically FALSE.

(b) To rewrite XOR, first distribute the NOT over the AND using DeMorgan's law:

NOT (p AND q) = NOT p OR NOT q

Then we can interchange the AND and ORs using their respective distributive properties. That is,

p XOR q = (p OR q) AND (NOT p OR NOT q)

= (p AND (NOT p OR NOT q)) OR (q AND (NOT p OR NOT q))

= ((p AND NOT p) OR (p AND NOT q)) OR ((q AND NOT p) OR (q AND NOT q))

Both (p AND NOT p) and (q AND NOT q) are tautologically FALSE, so the truth value of either OR depends only on the other statements, so we have

p XOR q = (p AND NOT q) OR (q AND NOT p)

Recall the definition of IFF:

p IFF q = (p IMP q) AND (q IMP p)

Also recall that IMP is logically equivalent to

p IMP q = p OR NOT q

Then we have

p IFF q = (p OR NOT q) AND (q OR NOT p)

so that its negation is

NOT (p IFF q) = NOT ((p OR NOT q) AND (q OR NOT p))

= NOT (p OR NOT q) OR NOT (q OR NOT p)

= (NOT p AND q) OR (NOT q AND p)

The statements in bold match, so p XOR q is indeed equivalent to NOT (p IFF q).

3 0
2 years ago
Please help this is the last problem on my homework and I don’t understand how to do it
malfutka [58]
When the lines are parallel and angles are given, and since a straight line is 180°, the 2 angles of the line intersecting the parallel lines have to add up to be 180. Therefore,
21. 31°
22. 96°
23. 149°
24. 84°
25. 53°
6 0
3 years ago
Read 2 more answers
Find the coordinates for the midpoint of the segment with endpoints given 12,4 and -8,8
borishaifa [10]
<h2>Hello!</h2>

The answer is:

The coordinates of the midpoint are:

x-coordinate=2\\y-coordinate=6

<h2>Why?</h2>

We can find the midpoint of the segment with the given endpoints using the following formula.

The midpoint of a segment is given by:

MidPoint=(\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2})

We are given the points:

(12,4)\\

and

(-8,8)\\

Where,

x_{1}=12\\y_{1}=4\\x_{2}=-8\\y_{2}=8

So, calculating the midpoint, we have:

MidPoint=(\frac{12+(-8)}{2},\frac{4+8}{2})

MidPoint=(\frac{4}{2},\frac{12}{2})

MidPoint=(2,6)

Hence, we have that the coordinates of the midpoint are:

x-coordinate=2\\y-coordinate=6

Have a nice day!

8 0
3 years ago
Read 2 more answers
Please help me c:
netineya [11]

Oscar played games vs number of points he scored is, C) positive, linear association.

Step-by-step explanation:

  • no association is when points Oscar graph will remain between 8to10.
  • number of games he scored his points remain the same which is mean.
  • non linear is only when there is no straight line passing.
  • Linear is either exponential or polynomial.
  • Positive as the game increase he scoring abilities increases.
  • Negative as the game increases his scoring decreases.
  • Negative x axis will have more number of points.
  • Negative y axis will high to low of the graph.
  • Linear lines are best way to predict a data doesn't work will all data.

8 0
3 years ago
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