Reflection across y=x is a special case transformation

The original triangle has vertices A(-5,1), B(-4,3), C(-2,1), D(-3,-1) so the transformed triangle has vertices
A'(1,-5), B'(3,-4), C'(1,-2), D'(-1,-3)
Choice A'(1,-5)
441 is odd, so we can't divide it by 2.
Since the sum of its digits is
, which is divisible by 3, we can divide 441 by 3, and we have

Which is still divisible by 3, because
. We have

49 is not divisible by 3 anymore, nor by 5 (it doesn't end with 0 or 5).
It is divisible by 7 though, we have

and finally,

So, the factorization of 441 is

Answer:
A Rigid Motion is a transformation that preserves length (distance preserving) and angle measure (angle preserving). Another name for a rigid motion is an isometry. A direct isometry preserves distance and orientation. Translations and Rotations are direct isometries.
Step-by-step explanation:
Answer:
Check the explanation
Step-by-step explanation:
(a)Let p be the smallest prime divisor of (n!)^2+1 if p<=n then p|n! Hence p can not divide (n!)^2+1. Hence p>n
(b) (n!)^2=-1 mod p now by format theorem (n!)^(p-1)= 1 mod p ( as p doesn't divide (n!)^2)
Hence (-1)^(p-1)/2= 1 mod p hence [ as p-1/2 is an integer] and hence( p-1)/2 is even number hence p is of the form 4k+1
(C) now let p be the largest prime of the form 4k+1 consider x= (p!)^2+1 . Let q be the smallest prime dividing x . By the previous exercises q> p and q is also of the form 4k+1 hence contradiction. Hence P_1 is infinite
We can find the height of the altitude by the ratio of sin. See my attachment.
sin of angle = side in front of the angle / hypotenuse
sin x = height/distance
If the two pilot is rising in an hour, then the first distance is 400 miles, the second distance is 300 miles.
Find the height of first pilotheight/distance = sin x
height/400 = sin 30°
height = sin 30° × 400
height = 1/2 × 400
height = 200
Find the height of second pilotheight/distance = sin x
height/300 = sin 40°
height = sin 40° × 300
height = 0.642 × 300
height = 192
So the first pilot traveling 400 mph with 30° is more quickly to reach high altitude than the second pilot traveling 300 mph with 40°