Answer:
130m
Explanation:
What we know:
- both tables have a mass of 29kg
- the gravitational force (F_g I'll call it) is a 4.24×10⁻¹⁰[N]
- G = 6.67×10⁻¹¹[m³/kg-s²]
- F_g = GMm/R²); where "M" and "m" are the two object's masses and "R" is the distance between them
With that information, all we need to do here is plug in the known values and then isolate "R" to find the distance between the two tables.
F_g = 4.24×10⁻¹⁰ = (6.67×10⁻¹¹)(29)(29)/R²
R = √[(6.67×10⁻¹¹)(29)(29)/4.24×10⁻¹⁰] = 132.2988...m = 130m
Well, first of all, the truck's velocity is constantly changing, not 'uniform'.
Velocity consists of speed and direction. So, even if the truck's speed is
constant, its direction keeps changing as long as it's on a circular curve,
so its velocity is constantly changing.
The force needed to keep a mass moving in a circle is
F = (mass) x (speed)² / (radius)
3300 N = (1600 kg) (13 m/s)² / R
3300 kg-m/s² = (1600 kg) (169 m²/s²) / R
R = (1600 kg) · (169 m²/s²) / (3300 kg·m/s²)
= (1600 · 169 / 3300) meters
= 81.9 meters
FALSE................................................................
Answer:
± (.021 ) ohm
Explanation:
In the addition of two physical quantities , the uncertainties are simply added .
So , net uncertainty in the value of R will be
± (.007 +.014)
=± (.021 ) ohm
Answer:
The maximum error is
Explanation:
From the question we are told that
The length is
The radius is
The pressure is
The rate is
The viscosity is
The error in the viscosity is mathematically represented as
Where
and
and
So
substituting values