This question is incomplete the complete question is
A diver bounces straight up from a diving board, avoiding the diving board on the way down, and falls feet first into a pool. She starts with a velocity of 4.00 m/s and her takeoff point is 1.80 m above the pool. (a) What is her highest point above the board? (b) How long a time are her feet in the air? (c) What is her velocity when her feet hit the water?
Answer:
(a) Xs=0.459m
(b) t=0.984 s
(c) Vc=6.65 m/s
Explanation:
(a) To reach maximum distance

(b) For Time
To find t we must find t1 and t2
as
t=t1+t2
For T1

For T2

For Total Time
t=t1+t2
t=0.306+0.6789
t=0.984s
(c) To find Vc
Vc=Vb+gt2
Vc=(0)+(9.8)(0.6789)
Vc=6.65 m/s
Divide 56 by 60 then x the answer by 6 then you get 5.6km which is your answer.
Answer:
The acceleration of the object is
Explanation:
Given:
Initial velocity of object
= 200 feet/second
Final velocity of object
= 50 feet/second
Time of travel = 5 seconds
To calculate acceleration of the object we will find the rate of change of velocity with respect to time.
So, acceleration
is given by:

where
represents final velocity,
represents initial velocity and
is time of travel.
Plugging in values to evaluate acceleration.



The acceleration of the object is
(Answer). The negative sign shows the object is slowing down.
Answer:
also increase
Explanation:
If the mass increases so will the weight.