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4 years ago

5

Which statement about moons is true?

1 answer:

kotegsom [21]4 years ago

8 0

Answer:

A

Explanation:

All of the other answers don't make much sense

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Why does water that is frozen in an ice cube tray stay in the shape of a cube when it is

quester [9]

The Answer is B : The water particles become locked in place.

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3 years ago

5. Which type of energy do all objects<br> contain?

Rainbow [258]

Answer:

kinetic energy

Explanation:

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3 years ago

A liquid is flowing through a horizontal pipe whose radius is m. The pipe bends straight upward through a height of 10.6 m and j

zaharov [31]

Answer:

Volume flow rate $= 1.81 * 10^{-2}$ meter cube per second

Explanation:

As we know that the

Pressure at the two ends would be the same along with volume of flow.

i.e

$P_1 = P_2$

and

$A_1 V_1 = A_2 V_2$

Re arranging the file, we get -

$V_1 = \frac{A_2 V_2}{A_1}$

The flow equation is

$\frac{1}{2}\rho * V_1^2 = \frac{1}{2}\rho * V_2^2 + \rho * g * h\\$

Substituting the value of $V_1$ in above equation, we get -

$V_2 = \sqrt{\frac{2gh}{(\frac{A_2}{A_1})^2-1} }$

Substituting the given values in above equation we get

$V_2 = \sqrt{\frac{2*9.8*10.6}{(\frac{\pi 0.04^2}{\pi 0.02^2} )^2 -1} }\\ V_2 = 3.61 m$

Volume flow rate

$Q_2 = A_2 V_2\\= \pi r_2^2V_2^2\\= 3.14 * 0.04^2 * 3.61 \\= 1.81 * 10^{-2}$

7 0

3 years ago

Two similar sized stones one heavy and one light dropped from the same height into a pond explain why the impact of the heavy st

Zigmanuir [339]

In energy point of view, the larger stone had more potential energy before dropping. impacting the water, the larger one, having more kinetic energy which changed from potential energy, tranfered energy to the water and formed wave. the amplitude of the wave indicate the energy of the wave. more energy more amplitude.

5 0

3 years ago

A 3-kg object is attached to a spring and moving in simple harmonic motion. Its angular frequency is 20 rads/sec. When the mass-

Trava [24]

Answer:19.5 J

Explanation:

Given

mass of block=3 kg

angular frequency=20 rad/sec

spring constant $k=\omega _n^2m=1200 N/m$

we know total energy remain conserved

$E_T at x=0.1 m$

$E_T=E_P+E_K$

Where $E_K$ =kinetic energy

$E_P$ =potential Energy

$E_P=\frac{1}{2}kx^2$

$E_P=600\times 0.01=6 J$

$E_K=\frac{1}{2}mv^2$

$E_K=\frac{1}{2}\times 3\times 3^2=13.5 J$

$E_T=13.5+6=19.5 J$

When mass reaches amplitude its velocity becomes zero

there is only potential energy which is equal to Total energy

$E_T=E_P=19.5 J$

7 0

3 years ago