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Arisa [49]
3 years ago
10

Or a hydrogen atom, which electronic transition would result in the emission of a photon with the highest energy?

Chemistry
1 answer:
ELEN [110]3 years ago
8 0
This electronic transition would result in the emission of a photon with the highest energy: 4p – 2s <span>This can be the same with the emission of 4f to 2s which would emit energy in the visible region. The energy in the visible region would emit more energy than in the infrared region which makes this emission to have the highest energy.</span>
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Write a balanced net ionic equation for the following reaction. BaCI2(aq)+H2SO4(aq) -&gt; BaSO4(s)+HCI (aq)
Sever21 [200]
Ba²⁺ + 2Cl⁻ + 2H⁺ + SO₄²⁻ = BaSO₄ (precipitate) + 2H⁺ + 2Cl⁻
Ba²⁺ + SO₄²⁻ = BaSO₄
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3 years ago
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Which describes an effect that ocean currents have on short-term climate change? Ocean currents increase the strength of prevail
Luba_88 [7]

Answer:

All the option are correct

Explanation:

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From a biological point of view, the ocean currents may be associated not only with the climate but also biogeochemical cycles through modifications in the distribution of heat and freshwater. Thus, the changes in ocean circulation may produce biogeographical shifts by affecting the local climate. The importance of ocean currents in affecting biodiversity is also represented by the equilibrium of coral reef ecosystems, where this equilibrium is broken up by factors such as transport of pollutants, temperature conditions, etc., which are known to alter thermosensitive coral species.

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3 years ago
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Describe any new ways you can change the polarity of the three-atom molecule.
yan [13]

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-  Replacing one or more atom with different atoms having electro negativity values also make molecular poles.

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5 0
3 years ago
What is the energy of a photon that emits a light of frequency 6.42 x 1014 Hz?<br><br>​
svetlana [45]

Answer:

Option B. 4.25×10¯¹⁹ J

Explanation:

From the question given above, the following data were obtained:

Frequency (f) = 6.42×10¹⁴ Hz

Energy (E) =?

Energy and frequency are related by the following equation:

Energy (E) = Planck's constant (h) × frequency (f)

E = hf

With the above formula, we can obtain the energy of the photon as follow:

Frequency (f) = 6.42×10¹⁴ Hz

Planck's constant (h) = 6.63×10¯³⁴ Js

Energy (E) =?

E = hf

E = 6.63×10¯³⁴ × 6.42×10¹⁴

E = 4.25×10¯¹⁹ J

Thus, the energy of the photon is 4.25×10¯¹⁹ J

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