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Arisa [49]
3 years ago
10

Or a hydrogen atom, which electronic transition would result in the emission of a photon with the highest energy?

Chemistry
1 answer:
ELEN [110]3 years ago
8 0
This electronic transition would result in the emission of a photon with the highest energy: 4p – 2s <span>This can be the same with the emission of 4f to 2s which would emit energy in the visible region. The energy in the visible region would emit more energy than in the infrared region which makes this emission to have the highest energy.</span>
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Explain each of these impacts and suggest a solution that would reduce the losses caused by bycatch.
Dennis_Churaev [7]

Answer:

Bycatch can negatively affect species such as dolphins, sea turtles, protected fish, and whales by harming animals, contributing to population declines, and impeding population recovery. Other impacts of fisheries on marine mammals may include removal of their preferred prey and sometimes habitat damage.

Explanation: hey could i get to kno u or sum

6 0
3 years ago
. Nhiệt độ ban đầu của 344 g một mẫu sắt là 18,2oC. Nếu mẫu sắt này hấp thụ 2,25 kJ nhiệt lượng thì nhiệt độ cuối của mẫu sắt nà
Mrrafil [7]

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8 0
3 years ago
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Compare melting point freezing point and boiling point
Tresset [83]
Melting point- the temperature at which a substance has changed from a solid to a liquid
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4 0
3 years ago
I’m kinda stuck with this part of the paper
zhenek [66]

Answer:

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Explanation:

6 0
3 years ago
For the reaction shown, identify the element oxidized, the element reduced, the oxidizing agent, and the reducing agent. KNO3 →
Vinvika [58]

Answer : The oxidizing element is N and reducing element is O. 

KNO_{3} is act as an oxidizing agent as well as reducing agent.

Explanation :

An Oxidizing agent is the agent which has ability to oxidize other or a higher in oxidation number.

Reducing agent is the agent which has ability to reduce other or lower in oxidation number.

The given reaction is :

KNO_{3} \rightarrow KNO_{2} +O_{2}

KNO_{3}  act as an oxidizing agent.

The oxidation number of N in KNO_{3} is calculated as:

(+1)+(x)+3(-2) = 0

x = +5

And the oxidation number of N in KNO_{2}  is calculated as:

(+1)+(x)+2(-2) = 0

x = +3

From the oxidation number method, we conclude that the oxidation number  reduced this means KNO_{3} itself get reduced to KNO_{2} and it can act as an oxidizing agent.

KNO_{3}  act as a reducing agent.

KNO_{3} \rightarrow KNO_{2} +O_{2}

The oxidation number of O in KNO_{3} is calculated as:

(+1)+(+5)+3(x) = 0

x = -2

The oxidation number of O in O_{2} is Zero (o).

Now, we conclude that the oxidation number increases this means KNO_{3} itself get oxidized to O_{2} and it can act as reducing agent.





                     

4 0
4 years ago
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