The value of the cosine ratio cos(L) is 5/13
<h3>How to determine the cosine ratio?</h3>
The complete question is added as an attachment
Start by calculating the hypotenuse (h) using
h^2 = 5^2 + 12^2
Evaluate the exponent
h^2 = 25 + 144
Evaluate the sum
h^2 = 169
Evaluate the exponent of both sides
h = 13
The cosine ratio is then calculated as:
cos(L) = KL/h
This gives
cos(L) =5/13
Hence, the value of the cosine ratio cos(L) is 5/13
Read more about right triangles at:
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-3(x-14)+9x=6x+24
-3x+42+9x=6x+24
-3x+9x-6x=-24-42
0=-18
Answer:
Option b
Step-by-step explanation:
To write the searched equation we must modify the function f (x) = | x | in the following way:
1. Do y = f(x + 4)
This operation horizontally shifts the function f(x) = | x | by a factor of 4 units to the left on the x axis.
y = | x +4 |
2. Do 
This operation horizontally expands the function f (x) = | x | in a factor of 4 units. 
3. Do 
This operation vertically shifts the function f (x) = | x | by a factor of 4 units down on the y-axis.

4. After these transformations the function f(x) = | x | it looks like:

Therefore the correct option is option b. You can verify that your vertex is at point (-4, -4) by making f (-4)

Use the slope formula to find the slope of a line given the coordinates of two points on the line. The slope formula is m=(y2-y1)/(x2-x1), or the change in the y values over the change in the x values.
-2x-y=3 ...(1)
x+2y=4 ...(2)
multiply (2) by 2 and add to (1)
-2x-y+2x+4y=3+8
3y=11
y=11/3
from (2)
x=4-2y=4-2(11/3)
or x=4-(22/3)
=(12-22)/3=-10/3