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3241004551 [841]
3 years ago
10

How to solve 6h-3.3h

Mathematics
1 answer:
LiRa [457]3 years ago
3 0

Answer:

2.7h

Step-by-step explanation:

The variable "h" does not matter.  Leave the "h" like it is, and just subtract.

Hope it helps!  Leave a comment if you have questions!

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(P+a)(V+b)=c,
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Answer:

PUSHIN

Step-by-step explanation:

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2 years ago
Which graph represents a function?
MissTica
The second to last one, looks like a really tall speed bump
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Express the integral as a limit of Riemann sums. Do not evaluate the limit. (Use the right endpoints of each subinterval as your
Veronika [31]

The expression of integral as a limit of Riemann sums of given integral \int\limits^5_b {1} \, x/(2+x^{3}) dxis 4 \lim_{n \to \infty}∑n(n+4i)/2n^{3}+(n+4i)^{3} from i=1 to i=n.

Given an integral \int\limits^5_b {1} \, x/(2+x^{3}) dx.

We are required to express the integral as a limit of Riemann sums.

An integral basically assigns numbers to functions in a way that describes displacement, area, volume, and other concepts that arise by combining infinite data.

A Riemann sum is basically a certain kind of approximation of an integral by a finite sum.

Using Riemann sums, we have :

\int\limits^b_a {f(x)} \, dx=\lim_{n \to \infty}∑f(a+iΔx)Δx ,here Δx=(b-a)/n

\int\limits^5_1 {x/(2+x^{3}) } \, dx=f(x)=x/2+x^{3}

⇒Δx=(5-1)/n=4/n

f(a+iΔx)=f(1+4i/n)

f(1+4i/n)=[n^{2}(n+4i)]/2n^{3}+(n+4i)^{3}

\lim_{n \to \infty}∑f(a+iΔx)Δx=

\lim_{n \to \infty}∑n^{2}(n+4i)/2n^{3}+(n+4i)^{3}4/n

=4\lim_{n \to \infty}∑n(n+4i)/2n^{3}+(n+4i)^{3}

Hence the expression of integral as a limit of Riemann sums of given integral \int\limits^5_b {1} \, x/(2+x^{3}) dxis 4 \lim_{n \to \infty}∑n(n+4i)/2n^{3}+(n+4i)^{3} from i=1 to i=n.

Learn more about integral at brainly.com/question/27419605

#SPJ4

5 0
1 year ago
Solve for x. 78(−32−48x)+36=23(−33x−18)−10x Enter your answer in the box. x =
Nina [5.8K]

Answer:

x=-0.688

Step-by-step explanation:

-2496-3744x+36 = -759x-414-10x

-2460-3744x = -769x-414

-2975x = 2046

5 0
3 years ago
2.5 pounds of grapes cost $2.25 what is the cost per pound
Sergeeva-Olga [200]

Answer:

$0.9 per pound

Step-by-step explanation:

$2.25 divided by 2.5

3 0
2 years ago
Read 2 more answers
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