Answer : Option A) 0.5 M NaCl.
Explanation : A solution can be called as a stronger electrolyte which when dissolved in aqueous solution and produce ions in the solutions and is easily decomposed by electrolysis. Amongst the given options NaCl produces Na ions and Cl ions on dissolving with water rest all are not so readily soluble in water. As only salts which belong to<span> Group I elements are soluble electrolytes.</span>
Answer: Please see answers in explanation column
Explanation:
Name Type of sugars
Sucrose Disaccharide
Sucrose, also called table sugar with molecular formulae C12H22O11 is a disaccharide composed of two monosaccharides ( 50%glucose + 50% fructose.).
Lactose Disaccharide
Lactose with molecular formula C12H22O11, found in milk is a disaccharide composed of two monosaccharides (galactose and glucose).
Fructose Monosaccharide
Fructose with molecular formulae C6H12O6 is a natural sugar mostly found in fruits.
Starch Polysaccharide
Starch ,a complex carbohydrate with molecular formula (C6H10O5)n, is a Polysaccharide containing many units of glucose joined together by 1,4 linkages. Sources of starch can be found in the parts of plants( roots, tubers etc).
Glucose monosaccharides
Glucose, is a simple sugar (monosaccharides) with the molecular formula C6H12O6. It is found in parts of plants as well as in humans and known as blood sugar because of its location in the bloodstream.
In science, the standard unit of mass is the kilogram (kg). A bowling ball has a mass of about 5 kilograms. A basketball has a mass of just over 0.5 kilogram. The mass of a basketball can easily be given in smaller units—grams.
I believe the answer is C !
<span>1.02x10^2 ml
Since molarity is defined as moles per liter, the product of the molarity and volume will remain constant as mole solvent is added. So let's set up an equality to express this
m0*v0 = m1*v1
where
m0, v0 = molarity and volume of original solution
m1, m1 = molarity and volume of final solution.
Solve for v0, then substitute the known values and calculate:
m0*v0 = m1*v1
v0 = (1.75 M * 500 ml)/8.61 M
v0 = (1.75 M * 500 ml)/8.61 M
V0 = 101.6260163
Rounding to 3 significant figures gives 102 ml.
So the original volume of the 8.61 M H2SO4 solution was 102 ml or 1.02x10^2 ml.</span>
