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Elden [556K]
1 year ago
15

Identify the type of sugar corresponding to each name. Sucrose Choose... Fructose Choose... Lactose Choose... Glucose Choose...

Starch
Chemistry
1 answer:
sergey [27]1 year ago
7 0

Answer: Please see answers in explanation column

Explanation:

Name                Type of sugars

Sucrose               Disaccharide

Sucrose, also called table sugar with molecular formulae C12H22O11  is a disaccharide  composed of two monosaccharides ( 50%glucose + 50%  fructose.).

Lactose                 Disaccharide

Lactose with molecular formula C12H22O11, found in milk is a disaccharide composed of two monosaccharides (galactose and glucose).

Fructose                 Monosaccharide  

Fructose with molecular formulae C6H12O6 is a natural sugar mostly found in fruits.

Starch                  Polysaccharide

Starch ,a complex carbohydrate with molecular formula  (C6H10O5)n,  is a Polysaccharide containing many  units of glucose joined together by 1,4 linkages. Sources of starch can be found in the parts of plants( roots, tubers etc).

Glucose                 monosaccharides

Glucose, is a simple sugar (monosaccharides) with the molecular formula C6H12O6.  It is found in parts of plants  as well as in humans and known as blood sugar because of its location in the bloodstream.

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Determine the molarity of a solution formed by dissolving 97.7 g libr in enough water to yield 750.0 ml of solution.
rewona [7]

Answer:

1.5 M.

Explanation:

  • Molarity (M) is defined as the no. of moles of solute dissolved in a 1.0 L of the solution.

<em>M = (no. of moles of LiBr)/(Volume of the solution (L).</em>

<em></em>

∵ no. of moles of LiBr = (mass/molar mass) of LiBr = (97.7 g)/(86.845 g/mol) = 1.125 mol.

Volume of the solution = 750.0 mL = 0.75 L.

∴ M = (no. of moles of luminol)/(Volume of the solution (L) = (1.125 mol)/(0.75 L) = 1.5 M.

3 0
3 years ago
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What does visible light include?
Hoochie [10]
I believe visible light is made from photons
4 0
3 years ago
When atoms react they form a chemical bond which is defined as?
Jet001 [13]
A force of attraction that holds atom together
When atoms react they form a chemical bond which is defined as a force of attraction that holds atom together. A force of attraction is defined as a kind of force that draws two or more objects together regardless of distance. There are two major categories of forces of attraction, one is intramolecular and intermolecular. Intramolecular forces is the presence of forces in atoms internally. While intermolecular is the force by which the force that is existent in two or more elements.



8 0
3 years ago
10 g of a solute is added to 1.00 L of pure water. Half of the added solute fails to dissolve. What can you conclude?
ryzh [129]

If in the solution, half of the added solute fails to dissolve. The solution started out supersaturated. The correct option is b.

<h3>What is supersaturation?</h3>

Supersaturation is the condition where the solutes exceed the amount that can be dissolved in a solution.

Supersaturation occurs when the solute no longer mix in the solution.

Thus, the correct option is b. The solution started out supersaturated.

Learn more about supersaturation

brainly.com/question/16817894

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5 0
2 years ago
A compound contains 1.2 g of carbon, 3.2 g of oxygen and 0.2g of hydrogen. Find the formula of the compound
Karolina [17]

Answer:

The empirical formula of the compound is C_{0.504}HO_{1.008}.

Explanation:

We need to determine the empirical formula in its simplest form, where hydrogen (H) is scaled up to a mole, since it has the molar mass, and both carbon (C) and oxygen (O) are also scaled up in the same magnitude. The empirical formula is of the form:

C_{x}HO_{y}

Where x, y are the number of moles of the carbon and oxygen, respectively.

The scale factor (r), no unit, is calculated by the following formula:

r = \frac{M_{H}}{m_{H}} (1)

Where:

m_{H} - Mass of hydrogen, in grams.

M_{H} - Molar mass of hydrogen, in grams per mole.

If we know that  M_{H} = 1.008\,\frac{g}{mol} and m_{H} = 0.2\,g, then the scale factor is:

r = \frac{1.008}{0.2}

r = 5.04

The molar masses of carbon (M_{C}) and oxygen (M_{O}) are 12.011\,\frac{g}{mol} and 15.999\,\frac{g}{mol}, then, the respective numbers of moles are: (r = 5.04, m_{C} = 1.2\,g, m_{O} = 3.2\,g)

Carbon

n_{C} = \frac{r\cdot m_{C}}{M_{C}} (2)

n_{C} = \frac{(5.04)\cdot (1.2\,g)}{12.011\,\frac{g}{mol} }

n_{C} = 0.504\,moles

Oxygen

n_{O} = \frac{r\cdot m_{O}}{M_{O}} (3)

n_{O} = \frac{(5.04)\cdot (3.2\,g)}{15.999\,\frac{g}{mol} }

n_{O} = 1.008\,moles

Hence, the empirical formula of the compound is C_{0.504}HO_{1.008}.

3 0
2 years ago
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