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3 years ago

PLEASE HELP ME WILL DO ANYTHING ‼️‼️

Chemistry

1 answer:

deff fn [24]3 years ago

6 0

Answer:

In first shell 2 electrons are present and 7 electrons are present in last shell

Explanation:

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What is the appropriate chemical formula for Iron(III) Sulfate? Sulfate is SO_4^2 Fe3SO4 O a . Fe2(SO4)3 O b. O c. Fe2SO4 O d. F

AnnyKZ [126]

Answer: The chemical formula of Iron (III) sulfate is $Fe_2(SO_4)_3$

Explanation:

Iron is the 26th element of periodic table having electronic configuration of $[Ar]3d^64s^2$ .

To form $Fe^{3+}$ ion, this element will loose 3 electrons.

Sulfate ion is a polyatomic ion having chemical formula of $SO_4^{2-}$

By criss-cross method, the oxidation state of the ions gets exchanged and they form the subscripts of the other ions. This results in the formation of a neutral compound.

So, the chemical formula for Iron (III) sulfate is $Fe_2(SO_4)_3$

4 0

3 years ago

Which of the following statements is correct concerning the class of reactions to be expected for benzene and cyclooctatetraene?

Sunny_sXe [5.5K]

Answer:

Both substances undergo substitution reactions.

Explanation:

Let us go back to the idea of aromaticity. Aromatic substances are said to possess (4n + 2) π electrons according to Huckel rule.

Aromatic substances are unusually stable and the aromatic ring can not be destroyed by addition reactions.

Since both benzene and cyclooctatetraene are both aromatic, they do not undergo addition reactions whereby the aromatic ring is destroyed. They both undergo substitution reaction in which the aromatic ring is maintained.

4 0

3 years ago

The total number of valence electrons in the phosphate ion is

Vitek1552 [10]

Answer:

Step-by-step explanation:

There are two ways you can count the valence electrons.

A. From the Periodic Table

1 × P (Group 15) = 5

4 × O (Group 16) = 4 × 6 = 24

+3 e⁻ (for the charges) = 3

Total = 32

B. From the Lewis structure

In the Lewis structure (below), each line (bond) represents a pair of bonding electrons, and each dot represents an unbound electron (half a lone pair).

5 lines (bonds) = 5 × 2 = 10

3 single-bonded O atoms = 3 × 6 = 18

1 double-bonded O atom = 4

Total = 32

4 0

4 years ago

Calculate the mole fraction of benzene in a mixture that contains 45.2 g of benzene and 115.8 g of toluene.

ololo11 [35]

molecular weight of toluene = 92 g/mol

C6 = 12 x 6 = 72

H5 = 1 x 5 =5

CH3 = 12 + 1 x 3 =15

molecular weight of benzene = 78 g/mol

C6 = 12 x 6 = 72

H6 = 1 x 6 = 6

moles toluene:

115.8 / (92 g/mol) = 1.25 mol

moles benzene:

45.2/ (78 g/mol) = 0.57mol

total moles: 1.25 + 0.57= 1.82 moles

mole fraction of toluene:

1.25 mol / 1.82 moles = 0.68

6 0

4 years ago

Zinc metal reacts with hydrochloric acid to produce zinc(II) chloride and hydrogen gas. How many liters of hydrogen gas will be

AleksAgata [21]

Answer:

0.120 L of hydrogen gas will be produced

Explanation:

Step 1: Data given

Mass of zinc = 10.0 grams

Volume of hydrochloric acid = 23.8 mL

Molarity of hydrochloric acid = 0.45 M

Molar mass of zinc =65.38 g/mol

Step 2: The balanced equation

Zn + 2HCl → ZnCl2 + H2

Step 3: Calculate moles Zinc

Moles Zn = mass Zn / molar mass Zn

Moles Zn = 10.0 grams / 65.38 g/mol

Moles Zn = 0.153 moles

Step 4: Calculate moles HCl

Moles HCl = molarity * volume

Moles HCl = 0.45 M * 0.0238 L

Moles HCl = 0.01071 moles

Step 5: Calculate limiting reactant

For 1 mol Zn, we need 2 moles HCl to produce 1 mol ZnCl2 and 1 mol H2

HCl is the limiting reactant. It will completely be consumed (0.01071 moles)

Zn is in excess. There will react 0.01071/2 = 0.005355 moles

There will remain 0.153 - 0.005355 = 0.147645 moles

Step 6: Calculate moles H2

For 1 mol Zn, we need 2 moles HCl to produce 1 mol ZnCl2 and 1 mol H2

For 0.01071 moles HCl we'll have 0.005355 moles H2

Step 7: Calculate volume H2

1 mol at STP = 22.4 L

0.005355 moles = 22.4 * 0.005355 = 0.120 L = 120 mL

0.120 L of hydrogen gas will be produced

4 0

4 years ago