Lead(II) nitrate will react with iron(III) chloride to produce the precipitate lead(II) chloride as shown in the balanced reaction
2FeCl3(aq) + 3Pb(NO3)2(aq) → 2Fe(NO3)3(aq) + 3PbCl2(s)
Calculating the amount of the precipitate lead(II) chloride each reactant will produce:
mol PbCl2 = 0.050L Pb(NO3)2 (0.100mol/1L)(3mol PbCl2/3mol Pb(NO3)2)
= 0.00500mol PbCl2
mol PbCl2 = 0.050L FeCl3 (0.100mol FeCl3/1L)(3mol PbCl2/2mol FeCl3) = 0.00750mol PbCl2
The reactant Pb(NO3)2 produces a lesser amount of the precipitate PbCl2, therefore, the lead(II) nitrate is the limiting reagent for this reaction.
A. The abundance of the 2nd isotope is 48.119%
B. The mass of the 2nd isotope is 108.905 amu
Let the 1st isotope be A
Let the 2nd isotope be B
A. Determination of the abundance of the 2nd isotope
Abundance of isotope A = 51.881%.
<h3>Abundance of isotope B =? </h3>
Abundance of B = 100 – A
Abundance of B = 100 – 51.881
<h3>Abundance of B = 48.119%</h3>
B. Determination of the mass of the 2nd isotope
Atomic mass of silver = 107.868 amu.
Mass of 1st isotope (A) = 106.906 amu
Abundance of isotope A (A%) = 51.881%.
Abundance of isotope B (B%) = 48.119%
<h3>Mass of 2nd isotope (B) =? </h3>
Therefore, the mass of the 2nd isotope is 108.905 amu
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An oxide of nitrogen contains 30.45 mass % N, if the molar mass is 90± 5 g/mol the molecular formula is N₂O₄.
<h3>What is molar mass?</h3>
The molar mass of a chemical compound is determined by dividing its mass by the quantity of that compound, expressed as the number of moles in the sample, measured in moles. A substance's molar mass is one of its properties. The compound's molar mass is an average over numerous samples, which frequently have different masses because of isotopes.
<h3>How to find the molecular formula?</h3>
The whole-number multiple is defined as follows.
Whole-number multiple =
The empirical formula mass is shown below.
Mw of empirical formula = Mw of N+ 2 x (Mw of O)
= 14.01 g/mol + 2 x (16.00 g/mol)
= 46.01 g/mol
With the given molar mass or the molecular formula mass, we can get the whole-number multiple for the compound.
Whole-number multiple = ≈ 2
Multiplying the subscripts of NO2 by 2, the molecular formula is N(1x2)O(2x2)= N2O4.
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