I think the answer is 42.
4+3p≥40
He needs to have 40 or more to get to the finals so 4+3p has to be 40 or more
Step-by-step explanation:
R = 6.5cm and r = 2.3 cm
area of the shaded region = area of the outer circle - area of the inner circle
= πR²-πr²
=π(R²-r²)
=π{(6.5)²-(2.3)²}
=π (42.25-5.29)
= 3.14× 36.96
= 115.866
= 116 cm²
4120_7 = 4•7³ + 1•7² + 2•7¹ + 0•7⁰
4120_7 = 4•343 + 1•49 + 2•7 + 0•1
4120_7 = 1372 + 49 + 14
4120_7 = 1435
In base 12, we use the digits 0-9 as well as A for 10 and B for 11. So
A3B_12 = 10•12² + 3•12¹ + 11•12⁰
A3B_12 = 10•144 + 3•12 + 11•1
A3B_12 = 1440 + 36 + 11
A3B_12 = 1487
In base 36, we assign values between 10 and 35 to the letters A-Z, so that
WXYZ_36 = 32•36³ + 33•36² + 34•36¹ + 35•36⁰
WXYZ_36 = 32•46656 + 33•1296 + 34•36 + 35•1
WXYZ_36 = 1492992 + 42768 + 1224 + 35
WXYZ_36 = 1537019
